Creating 2D dictionary in Python

61,669

Solution 1

It would have the following syntax

dict_names = {
    'd1': {
        'name': 'bob',
        'place': 'lawn',
        'animal': 'man'
    },
    'd2': {
        'name': 'spot',
        'place': 'bed',
        'animal': 'dog'
    }
}

You can then look things up like

>>> dict_names['d1']['name']
'bob'

To assign a new inner dict

dict_names['d1'] = {'name': 'bob', 'place': 'lawn', 'animal': 'man'}

To assign a specific value to an inner dict

dict_names['d1']['name'] = 'fred'

Solution 2

Something like this should work.

dictionary = dict()
dictionary[1] = dict()
dictionary[1][1] = 3
print(dictionary[1][1])

You can extend it to higher dimensions as well.

Solution 3

Something like this would work:

set1 = {
     'name': 'Michael',
     'place': 'London',
     ...
     }
# same for set2

d = dict()
d['set1'] = set1
d['set2'] = set2

Then you can do:

d['set1']['name']

etc. It is better to think about it as a nested structure (instead of a 2D matrix):

{
 'set1': {
         'name': 'Michael',
         'place': 'London',
         ...
         }
 'set2': {
         'name': 'Michael',
         'place': 'London',
         ...
         }
}

Take a look here for an easy way to visualize nested dictionaries.

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user2921139

I am a Pythonista and I love learning new stuff on Python everyday! Stackoverflow helps me seek knowledge and also provide help to other Pythonista's here.

Updated on January 11, 2022

Comments

  • user2921139
    user2921139 over 2 years

    I have a list of details from an output for "set1" which are like "name", "place", "animal", "thing" and a "set2" with the same details.

    I want to create a dictionary with dict_names[setx]['name']... etc On these lines.

    Is that the best way to do it? If not how do I do it?

    I am not sure how 2D works in dictionary.. Any pointers?

    • abarnert
      abarnert almost 10 years
      It would help to give a more specific and complete example. What's in setx, and what do you want dict_names[setx]['name'] to return?
  • user2921139
    user2921139 almost 10 years
    I have {'name':'bob', 'place':'lawn', 'animal':'man'} part created but how do I assign it as key to d1?
  • Cory Kramer
    Cory Kramer almost 10 years
    dict_names['d1'] = {'name':'bob', 'place':'lawn', 'animal':'man'}
  • user2921139
    user2921139 almost 10 years
    so this is like a regular 1D dictionary.
  • user2921139
    user2921139 almost 10 years
    Sorry - i followed the entire thing. Just took me a few minutes, oddly even though i understand the dictionary concept clearly. The big structures kind of scare me I think!
  • numerah
    numerah over 9 years
    this saves the repeated values
  • chiffa
    chiffa over 7 years
    How about the case when I need to get the top-level both by the first and second key - for instance, pull all the objects that have a "name" tag in them?
  • Noprogexprnce mathmtcn
    Noprogexprnce mathmtcn over 6 years
    Good answer! Is there a way we could do the above in a for loop; i.e. say there're k number of dictionaries with the same keys but different features. I'd like to combine them into a 2d dictionary in a for loop. I've tried initializing an empty dictionary and append. But that didn't work. Any help would be appreciated!