Creating a relative symlink in python without using os.chdir()
Solution 1
You could just set the second argument to the destination, like:
import os
os.symlink('file.ext', '/path/to/some/directory/symlink')
Solution 2
You can also use os.path.relpath()
so that you can use symlinks with relative paths. Say your script is in a directory foo/
and this directory has subdirectories src/
and dst/
, and you want to create relative symlinks in dst/
to point to the files in src/
. To do so, you can do:
import os
from glob import glob
for src_path in glob('src/*'):
os.symlink(
os.path.relpath(
src_path,
'dst/'
),
os.path.join('dst', os.path.basename(src_path))
)
Listing the contents of dst/
then shows:
1.txt -> ../src/1.txt
2.txt -> ../src/2.txt
Relative symlinks are useful for if you want to create a tarball of the whole foo
directory tree, as I don't believe tar
updates symlinks to point to the relative path inside of the generated tarball.
Josh
Updated on June 15, 2022Comments
-
Josh almost 2 years
Say I have a path to a file:
/path/to/some/directory/file.ext
In python, I'd like to create a symlink in the same directory as the file, that points to the file. I'd like to end up with this:
/path/to/some/directory/symlink -> file.ext
I can do this fairly easily using os.chdir() to cd into the directory and create the symlinks. But os.chdir() is not thread safe, so I'd like to avoid using it. Assuming that the current working directory of the process is not the directory with the file (os.getcwd() != '/path/to/some/directory'), what's the best way to do this?
I guess I could create a busted link in whatever directory I'm in, then move it to the directory with the file:
import os, shutil os.symlink('file.ext', 'symlink') shutil.move('symlink', '/path/to/some/directory/.')
Is there a better way to do this?
Note, I don't want to end up with is this:
/path/to/some/directory/symlink -> /path/to/some/directory/file.ext
-
Jan Vlcinsky almost 11 yearsJust make sure, the link file does not exist, or better, remove it
os.remove("/path/to/some/directory/symlink")
-
user855443 about 3 yearsjust a warning: your solution looks good and it impresed me. I tried to apply it in a slightly different situation.
relpath
seems -- according to other discussions -- not very general. the python relpath function is working properly only for directories, applied to full filepath it does not always produce the expected results (I observe typically that it includes/../..
when only/..
is requred.