date_format() expects parameter 1 to be DateTime, string given

24,872

Solution 1

The first parameter to date_format needs to be an object of DateTime class.

echo "<td>" . date_format( new DateTime($row['date']), 'd/m/Y H:i:s' ). "</td>";

or, alternatively

echo "<td>" . date_format( date_create($row['date']), 'd/m/Y H:i:s' ). "</td>";

Solution 2

Change your code to the following as provided in the PHP manual. As stated in the error you need to convert the value to DateTime object before outputting.

    while($row = $sql -> fetch(PDO::FETCH_ASSOC))
  {
$date = new DateTime($row['date']);
  ...
echo "<td>" . $date->format( $row['date'], 'd/m/Y H:i:s'). "";"</td>";
  ...

  }
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24,872
Klapsius
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Klapsius

Updated on December 23, 2020

Comments

  • Klapsius
    Klapsius over 3 years

    I'm trying to replace my queries to PDO query and I have problems with date formats. I need to print dates in format d/m/Y H:i:s but after PDO script runs it prints the date in this format Y-m-d H:i:s

        while($row = $sql -> fetch(PDO::FETCH_ASSOC))
      {
      ...
    echo "<td>" . date_format( $row['date'], 'd/m/Y H:i:s'). "";"</td>";
      ...
    
      }
    Warning: date_format() expects parameter 1 to be DateTime, string given in 
    

    But if I change the code to echo "<td>" . $row['date']. "";"</td>"; then it returns to Y-m-d H:i:s How can I get the previous format d/m/Y H:i:s?