Debugging current file in VS Code

30,520

Solution 1

Change to:

"program": "${file}"

Solution 2

For reference this is the full launch.json

{
  "launch": {
    "version": "0.2.0",
    "configurations": [
      {
        "name": "Node.js - Debug Current File",
        "type": "node",
        "request": "launch",
        "program": "${file}"
      }
    ]
  }
}

Solution 3

For a single file, you can skip the launch.json file entirely. Just click the green arrow in the debugger panel and choose Node as your environment.

From here.

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Updated on January 18, 2022

Comments

  • Admin
    Admin over 2 years

    I am writing javascript and am currently doing simple exercises/programs. At times, I wish to run my file for testing purposes. I am aware I could create an HTML file and do this within the console. In Sublime, there exists a way to "build" the current file and immediately see the results (say, whatever is sent to console.log).

    With VS Code, it seems that for every file I want to "build"/debug in this manner, I must manually change the launch.json file to reflect the name of the current program.

    I have been researching a way around this, and I learned that there are variables like ${file} , but when I use that in the launch.json "program" attribute, for example:

    "program": "${workspaceRoot}/${file}"
    

    with or without the workspaceRoot part, I get the following error:

    Attribute "program" does not exist" (file name here). 
    

    Am I missing a simple way to accomplish this, or must I keep editing launch.json every time I want to run the file?

    Thanks in advance!