Deleting vector of pointers
Solution 1
I would suggest either using a boost::pointer_vector, an std::vector<std::unique_ptr<Foo>>
, or roll out your own Foo
manager class which holds a vector<Foo*>
and takes care of deletions in the constructor (you should see this as the "expert" solution, and only attempt it if you fully understand exception safety). You don't want to be doing the deletion manually, that can easily lead to errors.
Solution 2
Your code is fine. However, using smart pointers should be the preferred choice (less code to write and much fewer opportunities for memory bugs).
Solution 3
Would the use of smart pointers a cleaner way to go ?
Yes.
And if one does not want to use smart pointers, would this use of vector be considered clean ?
I have no ideas, why someone doesn't want use smart pointers in C++, if it's not homework...
But, I think, it's better to use something like boost::pointer_containers
in this case.
Solution 4
If you're not using classes derived from Foo
, and Foo
is relatively inexpensive to copy construct, just use vector<Foo>
.
If your compiler supports move semantics there shouldn't be an issue.
Vince
Updated on June 04, 2022Comments
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Vince almost 2 years
I need to create pointers of instances of a class, and the program do not know at compilation time how many pointers I will create. For deletion, I was considering storing the pointers in a vector, and then deleting them one by one. Would the use of smart pointers a cleaner way to go ? And if one does not want to use smart pointers, would this use of vector be considered clean ?
Minimum code:
#include <vector> using namespace std; class Foo { public: Foo(); }; Foo::Foo(){} void createFooVector(int nb, std::vector<Foo*> &v){ for(int i=0;i<nb;i++){ Foo* f = new Foo(); v.push_back(f); } } int main(int argc, char *argv[]){ std::vector<Foo*> v; createFooVector(5,v); while (!v.empty()){ Foo* f = v.back(); v.pop_back(); delete f; } }
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Matthieu M. about 11 yearsI would not recommend the manager solution though; chances are the OP won't make it safe enough with regard to exceptions...
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Matthieu M. about 11 yearsWhether it's expensive to construct matters little, I think you were thinking about being expensive to copy. With move semantics though, it might not be much of an issue... and if worst come to worst, one can use the new
emplace_back
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Peter Wood about 11 years@Matthieu Yes, move semantics change everything. To clarify what I meant, to push a value into a vector, you have to construct it then the vector copy constructs another. I meant to indicate the need to take into consideration the construction of values in general. I will update to say
copy construct
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juanchopanza about 11 years@MatthieuM. Very true. I added a warning about that.