detecting the memory page size

Question

Is there a portable way to detect (programmatically) the memory page size using C or C++ code ?

Solution 1

Since Boost is a pretty portable library you could use mapped_region::get_page_size() function to retrieve the memory page size.

As for C++ Standard it gives no such a possibility.

Solution 2

C doesn't know anything about memory pages. On posix systems you can use long pagesize = sysconf(_SC_PAGE_SIZE);

Solution 3

Windows 10, Visual Studio 2017, C++. Get the page size in bytes.

int main()
{
    SYSTEM_INFO sysInfo;

    GetSystemInfo(&sysInfo);

    printf("%s %d\n\n", "PageSize[Bytes] :", sysInfo.dwPageSize);

    getchar();

    return 0;
}

Solution 4

Yes, this is platform-specific. On Linux there's sysconf(_SC_PAGESIZE), which also seems to be POSIX. A typical C library implements this using the auxiliary vector. If for some reason you don't have a C library or the auxiliary vector you could determine the page size like this:

size_t get_page_size(void)
{
    size_t n;
    char *p;
    int u;
    for (n = 1; n; n *= 2) {
        p = mmap(0, n * 2, PROT_NONE, MAP_ANONYMOUS | MAP_PRIVATE, -1, 0);
        if (p == MAP_FAILED)
            return -1;
        u = munmap(p + n, n);
        munmap(p, n * 2);
        if (!u)
            return n;
    }
    return -1;
}

That's also POSIX, I think. It relies on there being some free memory, but it only needs two consecutive pages. It might be useful in some (weird) circumstances.

Solution 5

Across operating systems, no.

On Linux systems:

#include <unistd.h>
long sz = sysconf (_SC_PAGESIZE);

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Comments

[Admin]

No, there isn't.

[zvrba]

No there isn't because C and C++ exist also for platforms without virtual memory.

[kfsone]

Question says 'C', 'C++' and 'portable' and on top of that you managed to not even describe how to get from that to a page size.

[kfsone]

Disconnect between your explanation and the conclusion; applying the same logic would tell us that determining the size of a pointer is platform specific.