Differences between \W, \\W, [^a-zA-Z0-9_] in regular expression

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However, the following code could not even compile in Java

Java has no idea that the string is going to regex engine. Anything in doublequotes is a string literal to Java compiler, so it tries to interpret \W as a Java escape sequence, which does not exist. This trigger a compile-time error.

If I use only \\W rather than \W, the above code turns out to be correct.

This is because \\ is a valid escape sequence, which means "a single slash". When you put two slashes inside a string literal, Java compiler removes one slash, so regex engine sees \W, not \\W

So, what is the differences between \W, \\W, and when to use brackets like [^a-zA-Z0-9_]

The third one is a longer version of the second one; the first one does not compile.

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Yao
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Yao

Updated on June 05, 2022

Comments

  • Yao
    Yao almost 2 years

    I am trying to find all characters, which are not letters(upper/lowercase), numbers, and underscore, and remove it.

    stringA.replaceAll("[^a-zA-Z0-9_]","")   // works perfectly fine
    

    However, the following code could not even compile in Java:

    stringA.replaceAll("\W","");
    // or also
    stringA.replaceAll("[\W]","");
    // or also
    stringA.replaceAll("[\\W]","");
    

    If I use only "\\W" rather than "\W", the above code turns out to be correct.
    So, what is the differences between \W, \\W, and when to use brackets like [^a-zA-Z0-9_]