Django array or list output?
You want a dict, which is Python's associative data structure, whereas you are creating a list.
But I'm not sure I understand your problem. Why not just pass your media
collection into the template and iterate like this:
{% for file in media %}
<a href="{{ file.url }}">{{ file.title }}</a>
{% endfor %}
EDIT
Based on your comment, I now presume you are looking for something like this:
thumbnail_list = []
for file in media:
file_info = {}
file_info['url'] = file.url
file_info['title'] = file.title
thumbnail_list.append(file_info)
{% for file in thumbnail_list %}
<a href="{{ file.url }}">{{ file.title }}</a>
{% endfor %}
You can create a list, then for each file, append a dictionary into that list after you've processed the URL, title, or whatever.
Or, you could create your own class that encapsulates this a little better in case you have other logic to apply:
class FileInfo(object):
def __init__(self, file):
self.url = file.url # do whatever
self.title = file.title # do whatever
thumbnail_list = []
for file in media:
thumbnail_list.append(FileInfo(file))
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Admin
Updated on July 09, 2022Comments
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Admin almost 2 years
I'm pulling a set of image urls and their respective titles. I've tried creating a hash or associative array, but the data seems to overwrite so I only end up with the last item in the array.
For example;
thumbnail_list = [] for file in media: thumbnail_list['url'] = file.url thumbnail_list['title'] = file.title
I've even tried creating two lists and putting them in a larger one.
thumbnail_list.append('foo') thumbnail_urls.append('bar') all_thumbs = [thumbnail_list], [thumbnail_urls]
I'm trying to create a link out of this data:
<a href="image-url">image title</a>
I keep getting close, but I end up looping over too much data or all of the data at once in my django template.
Ideas?
Edit: Maybe zip() is what I need?
questions = ['name', 'quest', 'favorite color'] answers = ['lancelot', 'the holy grail', 'blue'] for q, a in zip(questions, answers): print 'What is your {0}? It is {1}.'.format(q, a)
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Admin over 14 yearsHi Joe - I need to do a string replace on the URL and also not output any images that don't have a title. So I can only do that on the python side, correct?
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Admin over 14 yearsUGH! I should have seen this earlier. thank you so much! Does that class FileInfo have to return anything or can I call it as is? e.g.; return self;
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Joe Holloway over 14 yearsThe
__init__
method is the Python constructor it doesn't need to return anything as it's return value is implied to be the new object.file_info = FileInfo(...)