Django: How to make a form with custom templating?
Solution 1
<form action="/contact/" method="post">
{% for field in form %}
<div class="fieldWrapper">
{{ field.errors }}
{{ field.label_tag }}: {{ field }}
</div>
{% endfor %}
<p><input type="submit" value="Send message" /></p>
</form>
You can find the complete documentation here: http://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template
Solution 2
I don't think you need a formset here. Take a look here if you want a custom template for one view. If you want to create your own {{ form.as_foobar }}, just subclass forms.Form, something like this:
class MyForm(forms.Form):
def as_foobar(self):
return self._html_output(
normal_row = u'%(label)s %(field)s%(help_text)s',
error_row = u'%s',
row_ender = '',
help_text_html = u' %s',
errors_on_separate_row = False)
and just use it in your forms.py:
class ContactForm(MyForm):
# ..
Solution 3
For whoever needs the <table>
version of jbcurtin's answer:
<form method="post">{% csrf_token %}
<table>
{% for field in form %}
<tr>
<th>{{field.label_tag}}</th>
<td>
{{ field.errors }}
{{ field }}
</td>
</tr>
{% endfor %}
</table>
<hr/>
<input type="submit" value="Conferma" />
</form>
Solution 4
Looks like you might be interested in django-floppyforms (docs), which gives you much more control over field rendering.
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Nick Heiner
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Updated on July 09, 2022Comments
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Nick Heiner almost 2 years
I have a model:
class Setting(models.Model): class Meta: abstract = True name = models.CharField(max_length=120, primary_key=True) description = models.CharField(max_length=300, blank=True) class IntegerSetting(Setting): value = models.IntegerField()
I would like to create a form that looks something like:
<form method="POST" action=""> {% for model in models %} <label>{{model.name}}</label> <input value='{{model.value}}' /> <p>{{model.description}}</p> {% endfor %} </form>
I'm not quite sure how to go about doing this. Perhaps I need to use a formset?
from django.forms.models import modelformset_factory from apps.about.models import Setting, IntegerSetting def site_settings(request): formset = modelformset_factory(IntegerSetting)() return render_to_response("about/admin/site-settings.html", {'formset': formset}, RequestContext(request, {}))
Then in the template, I'd want to render the form differently than default. I'm not quite sure how to go about accessing the model properties, however. Is this the right approach, or is there another way I should be going about doing this?
Update: This is what I'm currently doing. It renders exactly as I'd like it to, aside from the styling. However, I feel that it's deeply hacky:
class SettingsForm(ModelForm): class Meta: model = IntegerSetting def as_table(self): bound_field = BoundField(self, self.fields['value'], 'value') return mark_safe("<tr><td><label>%s</label></td><td>%s\n<p class='help'>%s</p></td></tr>" % (self.instance.name, self.instance.description, bound_field.__unicode__())) def edit_settings(request): forms = [SettingsForm(instance=intSetting) for intSetting in IntegerSetting.objects.all()] return render_to_response("admin/edit-settings.html", {'forms': forms}, RequestContext(request, {}))
edit-settings.html:
{% extends "admin/base_site.html" %} {% block title %}System Settings{% endblock %} {% block content %} <form method="post" action=""> <table> {% for form in forms %} {{form}} {% endfor %} </table> </form> {% endblock %}
Is there a better approach to this?
Also, I'm not sure if I'll encounter problems when the form is submitted or not.
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SashaN about 13 yearsAlso I don't see to the point of using formsets. Doing something like this: from django.forms import ModelForm class IntegerSettingForm(ModelForm): class Meta: model = IntegerSetting should create a IntegerSettingForm class, which you can use to create your form instances in views.
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Nick Heiner about 13 yearsThis prints all the fields, but I want to use the value of one field as a label, and only have one field actually be an input.
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Nick Heiner about 13 yearsThe documentation you attached was useful, but it didn't mention a field attribute to print the value, not the widget. That's what I really want.
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Nick Heiner about 13 yearsAnd how would I get the results of
as_foobar
in the template? -
Nick Heiner about 13 yearsAlso, this is specifying the output on a field level, right? What I need is: "Model.name.value: Model.value.value (Model.description.value)"
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jbcurtin about 13 yearsIf you don't want the value to be editable, set 'editable' to false on the model and the form field will pick up on this.
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Apollo Data over 7 yearsYou'd use {{ form.as_foobar }} (similar to form.as_p) in the template. Replace 'form' with whatever your form variable is called.