Don't load hidden images
Solution 1
Here's a jQuery solution:
$(function () {
$("img").not(":visible").each(function () {
$(this).data("src", this.src);
this.src = "";
});
var reveal = function (selector) {
var img = $(selector);
img[0].src = img.data("src");
}
});
It's similar to your solution, except it doesn't use the fakeSrc
attribute in the markup. It clears the src
attribute to stop it from loading and stores it elsewhere. Once you are ready to show the image, you use the reveal
function much like you do in your solution. I apologize if you do not use jQuery, but the process should be transferable to whichever framework (if any) that you use.
Note: This code specifically must be ran before the window has fired the load
event but after the DOM has been loaded.
Solution 2
The browser will load any images that has a src
attribute set, so what you want to do is to use data-src
in the markup and use JavaScript to set the src
attribute when you want it to load.
<img class="hidden" data-src="url/to/image.jpg" />
I created this tiny plugin that will take care of the problem:
(function($){
// Bind the function to global jQuery object.
$.fn.reveal = function(){
// Arguments is a variable which is available within all functions
// and returns an object which holds the arguments passed.
// It is not really an array, so by calling Array.prototype
// he is actually casting it into an array.
var args = Array.prototype.slice.call(arguments);
// For each elements that matches the selector:
return this.each(function(){
// this is the dom element, so encapsulate the element with jQuery.
var img = $(this),
src = img.data("src");
// If there is a data-src attribute, set the attribute
// src to make load the image and bind an onload event.
src && img.attr("src", src).load(function(){
// Call the first argument passed (like fadeIn, slideIn, default is 'show').
// This piece is like doing img.fadeIn(1000) but in a more dynamic way.
img[args[0]||"show"].apply(img, args.splice(1));
});
});
}
}(jQuery));
Execute .reveal
on the image(s) you want to load/show:
$("img.hidden").reveal("fadeIn", 1000);
Solution 3
It partially depends on how your images must be placed in your code. Are you able to display the images as the background of a <div>, or are you required to use the <img> tag? If you need the <img> tag, you may be screwed depending on the browser being used. Some browsers are smart enough to recognize when an image is inside of a hidden object or in an object of 0 width/height and not load it since it's essentially invisible, anyway. For this reason many people will suggest putting an image in a 1x1 pixel <span> if you want the image to be pre-loaded but not visible.
If you don't require the <img> tag, most browsers won't load images referenced by CSS until the element in question becomes visible.
Mind you that short of using AJAX to download the image there's no way to be 100% sure the browser won't pre-load the image anyway. It's not unbelievable that a browser would want to pre-load anything it assumes may be used later in order to "speed up" the average load times.
Solution 4
Weirdly, there's no answer about native lazy loading which is implemented in the majority of the browsers already.
you can do it by adding loading="lazy"
attribute to your image.
Addy Osmani wrote a great article about it. You can read more about lazy loading here: https://addyosmani.com/blog/lazy-loading/
JoJo
Updated on August 21, 2022Comments
-
JoJo over 1 year
I have a bunch of hidden images on my website. Their container DIVs have style="display: none". Depending on the user's actions, some images may be revealed via javascript. The problem is that all my images are loaded upon opening the page. I would like to put less strain on the server by only loading images that eventually become visible. I was wondering if there was a pure CSS way to do this. Here are two hacky/complicated ways I am currently doing it. As you can see, it's not clean code.
<div id="hiddenDiv"> <img src="spacer.gif" /> </div> .reveal .img { background-image: url(flower.png); } $('hiddenDiv').addClassName('reveal');
Here is method 2:
<img id="flower" fakeSrc="flower.png" /> function revealImage(id) { $('id').writeAttribute( 'src', $('id').readAttribute('fakeSrc') ); } revealImage('flower');