Download file through an ajax call php
Solution 1
AJAX isn't for downloading files. Pop up a new window with the download link as its address, or do document.location = ...
.
Solution 2
A very simple solution using jQuery:
on the client side:
$('.act_download_statement').click(function(e){
e.preventDefault();
form = $('#my_form');
form.submit();
});
and on the server side, make sure you send back the correct Content-Type
header, so the browser will know its an attachment and the download will begin.
Solution 3
@joe : Many thanks, this was a good heads up!
I had a slightly harder problem: 1. sending an AJAX request with POST data, for the server to produce a ZIP file 2. getting a response back 3. download the ZIP file
So that's how I did it (using JQuery to handle the AJAX request):
Initial post request:
var parameters = { pid : "mypid", "files[]": ["file1.jpg","file2.jpg","file3.jpg"] }
var options = { url: "request/url",//replace with your request url type: "POST",//replace with your request type data: parameters,//see above context: document.body,//replace with your contex success: function(data){ if (data) { if (data.path) { //Create an hidden iframe, with the 'src' attribute set to the created ZIP file. var dlif = $('
<iframe/>
',{'src':data.path}).hide(); //Append the iFrame to the context this.append(dlif); } else if (data.error) { alert(data.error); } else { alert('Something went wrong'); } } } }; $.ajax(options);
The "request/url" handles the zip creation (off topic, so I wont post the full code) and returns the following JSON object. Something like:
//Code to create the zip file
//......
//Id of the file
$zipid = "myzipfile.zip"
//Download Link - it can be prettier
$dlink = 'http://'.$_SERVER["SERVER_NAME"].'/request/download&file='.$zipid;
//JSON response to be handled on the client side
$result = '{"success":1,"path":"'.$dlink.'","error":null}';
header('Content-type: application/json;');
echo $result;
The "request/download" can perform some security checks, if needed, and generate the file transfer:
$fn = $_GET['file'];
if ($fn) {
//Perform security checks
//.....check user session/role/whatever
$result = $_SERVER['DOCUMENT_ROOT'].'/path/to/file/'.$fn;
if (file_exists($result)) {
header('Content-Description: File Transfer');
header('Content-Type: application/force-download');
header('Content-Disposition: attachment; filename='.basename($result));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: ' . filesize($result));
ob_clean();
flush();
readfile($result);
@unlink($result);
}
}
Solution 4
I have accomplished this with a hidden iframe. I use perl, not php, so will just give concept, not code solution.
Client sends Ajax request to server, causing the file content to be generated. This is saved as a temp file on the server, and the filename is returned to the client.
Client (javascript) receives filename, and sets the iframe src to some url that will deliver the file, like:
$('iframe_dl').src="/app?download=1&filename=" + the_filename
Server slurps the file, unlinks it, and sends the stream to the client, with these headers:
Content-Type:'application/force-download'
Content-Disposition:'attachment; filename=the_filename'
Works like a charm.
Solution 5
You can't download the file directly via ajax.
You can put a link on the page with the URL to your file (returned from the ajax call) or another way is to use a hidden iframe
and set the URL of the source of that iframe
dynamically. This way you can download the file without refreshing the page.
Here is the code
$.ajax({
url : "yourURL.php",
type : "GET",
success : function(data) {
$("#iframeID").attr('src', 'downloadFileURL');
}
});
theking963
Updated on March 16, 2020Comments
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theking963 about 4 years
I have a button and
onclick
it will call an ajax function.Here is my ajax function
function csv(){ ajaxRequest = ajax();//ajax() is function that has all the XML HTTP Requests postdata = "data=" + document.getElementById("id").value; ajaxRequest.onreadystatechange = function(){ var ajaxDisplay = document.getElementById('ajaxDiv'); if(ajaxRequest.readyState == 4 && ajaxRequest.status==200){ ajaxDisplay.innerHTML = ajaxRequest.responseText; } } ajaxRequest.open("POST","csv.php",false); ajaxRequest.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded'); ajaxRequest.send(postdata); }
I create the csv file based on the user input. After it's created I want it to prompt download or force download(preferably force). I am using the following script at the end of the php file to download the file. If I run this script in a separate file it works fine.
$fileName = 'file.csv'; $downloadFileName = 'newfile.csv'; if (file_exists($fileName)) { header('Content-Description: File Transfer'); header('Content-Type: text/csv'); header('Content-Disposition: attachment; filename='.$downloadFileName); ob_clean(); flush(); readfile($fileName); exit; } echo "done";
But If I run it at the end of csv.php it outputs the contents of the file.csv into the page(into the ajaxDiv) instead of downloading.
Is there a way to force download the file at the end of csv.php?
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yitwail almost 11 yearsI believe technically it's better to set
window.location
; see this discussion: stackoverflow.com/questions/7857878/… -
stephen.hanson almost 11 years+1 This worked great for me for POSTing data to the server and getting a ZIP file download as the response. No page reload.
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larsAnders about 10 yearsPosting relevant code would help illustrate what you're trying to say here.
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Naimish B. Makwana about 10 yearson your ajax success response you can set the hidden iframe src
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Ilan Biala almost 10 yearsCan you give a little more detail and provide some code on what happens on both ends?
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neel shah almost 10 yearscode is nice but what happens error occurs it is redirected a error page which is not required
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Sunil Pachlangia about 9 yearsWhat if i want to show some loader for time being business logics are implementing and creating file content.
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Mike Wells over 7 yearsJust the & needed changing to a ? for the query string. Thanks for the awesome help with this though! - I tried to do an edit but it was such a small one it wouldn't let me!! $dlink = 'http://'.$_SERVER["SERVER_NAME"].'/request/download?file='.$zipid;
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Daniel about 6 yearsWhy is AJAX not for downloading files?
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Zach Smith over 4 yearsis "slurps" a technical term?
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Ionel Lupu about 4 yearsI can't set window.location because I need to set some special headers for my request