Dynamically create PHP object based on string

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Solution 1

But know of no way to dynamically create a type based on a string. How does one do this?

You can do it quite easily and naturally:

$type = 'myclass';

$instance = new $type;

If your query is returning an associative array, you can assign properties using similar syntax:

// build object
$type = $row['type'];
$instance = new $type;

// remove 'type' so we don't set $instance->type = 'foo' or 'bar'
unset($row['type']);  

// assign properties
foreach ($row as $property => $value) {
   $instance->$property = $value;
}

Solution 2

There's a very neat syntax you can use that I learned about a couple of months ago that does not rely on a temporary variable. Here's an example where I use a POST variable to load a specific class:

$eb = new ${!${''} = $_POST['entity'] . 'Binding'}();

In your specific case though, you would be able to solve it by using PDO. It has a fetch mode that allows the first column's value to be the class the row instantiates into.

$sth->fetch(PDO::FETCH_CLASS | PDO::FETCH_CLASSTYPE);

Solution 3

$instance = new $classname; // i.e. $type in your case

Works very well...

Solution 4

Below is what I was looking for when I came to this thread. use {"objectName"} (brackets) to declare or reference the object name in the form of a string.

$gameData = new stdClass();
$gameData->location = new stdClass();
$basementstring = "basement";

class tLocation {
    public $description;
}

$gameData->location->{'darkHouse'} = new tLocation;
$gameData->location->{"darkHouse"}->description = "You walkinto a dusty old house";


$gameData->location->{$basementstring} = new tLocation;
$gameData->location->{"basement"}->description = "its really damp down here.";

//var_dump($gameData); 
echo $gameData->location->basement->description;

This way of referring to the object seems to be interchangeable. I couldn't find the answer so i had to fool around with it Until I found a way.

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Mat Kelly
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Mat Kelly

Updated on September 11, 2020

Comments

  • Mat Kelly
    Mat Kelly over 3 years

    I would like to create an object in PHP based on a type defined by a string in a MySQL database. The database table has columns and sample data of:

     id | type | propertyVal
    ----+------+-------------
      1 | foo  | lorum
      2 | bar  | ipsum
    

    ...with PHP data types

    class ParentClass {...}
    class Foo extends ParentClass {private $id, $propertyVal; ...}
    class Bar extends ParentClass {private $id, $propertyVal; ...} 
    //...(more classes)...
    

    Using only one query, I would like to SELECT a row by id and create an object of the type define the table's type column with other columns in the SELECTed row being assigned to the newly created object.

    I was thinking that using:

    1. mysql_fetch_object()
    2. Reading the type attribute
    3. Creating an object with type defined by type attribute

    But know of no way to dynamically create a type based on a string. How does one do this?

  • goat
    goat about 14 years
    You can also pass arguments to the constructor $instance = new $type(5, 'hi');
  • FrancescoMM
    FrancescoMM almost 11 years
    I don't get it, apparently you would get $eb= new ${FALSE}(); or am I missing something??
  • silkfire
    silkfire almost 11 years
    The reason this hack works is because ${false} evaluates to ${''} (same thing as writing (string)false) and the variable with the name [empty string] is the one we just created in the inner bracket clause. Very nifty.
  • Em.MF
    Em.MF over 3 years
    note that className must be a full-path, valid address of class, for example: ` $type = "app\models\MyClass"; `
  • algo
    algo over 2 years
    But then how do you add the arguments of the constructor? Is it valid to do: $instance = new $classname($parameterA, $parameterB);
  • algo
    algo over 2 years
    What is the name of this syntax? Where can I read more about it? Because I am not understanding it.