Efficient element-wise multiplication of a matrix and a vector in TensorFlow

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The simplest code to do this relies on the broadcasting behavior of tf.multiply()*, which is based on numpy's broadcasting behavior:

x = tf.constant(5.0, shape=[5, 6])
w = tf.constant([0.0, 1.0, 2.0, 3.0, 4.0, 5.0])
xw = tf.multiply(x, w)
max_in_rows = tf.reduce_max(xw, 1)

sess = tf.Session()
print sess.run(xw)
# ==> [[0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
#      [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
#      [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
#      [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
#      [0.0, 5.0, 10.0, 15.0, 20.0, 25.0]]

print sess.run(max_in_rows)
# ==> [25.0, 25.0, 25.0, 25.0, 25.0]

* In older versions of TensorFlow, tf.multiply() was called tf.mul(). You can also use the * operator (i.e. xw = x * w) to perform the same operation.

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Andrzej Pronobis
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Updated on June 20, 2020

Comments

  • Andrzej Pronobis
    Andrzej Pronobis almost 4 years

    What would be the most efficient way to multiply (element-wise) a 2D tensor (matrix):

    x11 x12 .. x1N
    ...
    xM1 xM2 .. xMN
    

    by a vertical vector:

    w1
    ...
    wN
    

    to obtain a new matrix:

    x11*w1 x12*w2 ... x1N*wN
    ...
    xM1*w1 xM2*w2 ... xMN*wN
    

    To give some context, we have M data samples in a batch that can be processed in parallel, and each N-element sample must be multiplied by weights w stored in a variable to eventually pick the largest Xij*wj for each row i.