ExceptionInInitializerError in Android app?

18,965

Solution 1

Based on this documentation An ExceptionInInitializerError is thrown to indicate that an exception occurred during evaluation of a static initializer or the initializer for a static variable. Check your code has any static initialization logic.

Solution 2

If your android version is 11 or higher you might encounter java.lang.ExceptionInInitializerError and IllegalStateException for which you will need to add latest okhttp3 dependencies which are:

implementation 'com.squareup.okhttp3:okhttp:4.9.1'  

and

implementation 'com.squareup.okhttp3:logging-interceptor:4.9.0'

Solution 3

java.lang.ExceptionInInitializerError android OS 11

if this is related to OkHttp then update your version 4.4.0.

In this version its fixed.

implementation 'com.squareup.okhttp3:logging-interceptor:4.4.0'

thanks.

Share:
18,965

Related videos on Youtube

Naveen
Author by

Naveen

Geek :)

Updated on June 04, 2022

Comments

  • Naveen
    Naveen almost 2 years

    In my Android app the WebView activity class has following line,

    webView.addJavascriptInterface(new JSInterface(this), "Android");   
    

    And in JSInterface class, I'm initializing Google "SpreadSheetService" like below,

    import com.google.gdata.client.spreadsheet.SpreadsheetService;
    
    --- some more imports ---
    
    
    public class JSInterface {
        Context mContext;
    
        public SpreadsheetService service;
    
        /** Instantiate the interface and set the context */
        JSInterface(Context c) {
            mContext = c;
            service = new SpreadsheetService("List Demo");
        }
    
        ------- some more code -----
    

    When I run the application I'm getting the following exception,

    01-19 21:38:00.652: E/AndroidRuntime(4085): java.lang.ExceptionInInitializerError
    

    which has the below trace

    01-19 21:38:00.652: E/AndroidRuntime(4085): FATAL EXCEPTION: main
    01-19 21:38:00.652: E/AndroidRuntime(4085): java.lang.ExceptionInInitializerError
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at com.android.quotes.JSInterface.<init>(JSInterface.java:33)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at com.android.quotes.CHQuotesActivity.onCreate(CHQuotesActivity.java:19)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.Activity.performCreate(Activity.java:4465)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1919)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1980)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.ActivityThread.access$600(ActivityThread.java:122)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1146)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.os.Handler.dispatchMessage(Handler.java:99)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.os.Looper.loop(Looper.java:137)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at android.app.ActivityThread.main(ActivityThread.java:4340)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at java.lang.reflect.Method.invokeNative(Native Method)
    01-19 21:38:00.652: E/AndroidRuntime(4085):     at java.lang.reflect.Method.invoke(Method.java:511)
    

    I searched Google, but didnt get any solution for this.. Any idea on why I'm getting this exception??

    Peter

  • IgorGanapolsky
    IgorGanapolsky over 10 years
    Yeah, but what could be the problem? A static member should have no issues being accessed, hence it is static.
  • kosa
    kosa over 10 years
    @IgorGanapolsky: It is not due to being accessed, it is because of value being initialized is not properly constructed. The right side part of static variable.
  • IgorGanapolsky
    IgorGanapolsky over 10 years
    Interesting, initialized to what? An inconvertible type or null?
  • kosa
    kosa over 10 years
    @IgorGanapolsky: My guess is, some class instance, which is either throwing exception (or) causing some bad dependency.
  • McLan
    McLan about 7 years
    I am using a library in my app. For specific class in that library, whenever I create a new instance of it, my app crashes and gives me the same exception. Since it is a library class, it means I cannot change any thing in it. At the same time, I want to use it is functionality inside that class's methods. I am totally stuck and cannto find a way to solve this, any suggestions ? thanks
  • kosa
    kosa about 7 years
    @Suda.nese I would suggest create new question and refer this question, you could get lot of answers.
  • McLan
    McLan about 7 years
    @Nambari : I've already done so here : stackoverflow.com/q/42227184/2135363 .. and here : stackoverflow.com/q/42248119/2135363 .. Please have a look.
  • user158
    user158 over 4 years
    @McLan did you found a solution to your problem?
  • McLan
    McLan over 4 years
    @user158 can’t remember. But will check for you.