Expected to return a value in arrow; function array-callback-return. Why?
Solution 1
Try Changing map(() => {}) to map(() => ())
{} - Creates a code block that expects an explicit return
statement.
With () - implicit return takes place.
Solution 2
Your specific example is:
data.map(users => {
console.log(users);
});
Where data
is the following array:
[
{id: 1, username: "Foo"},
{id: 2, username: "Bar"},
]
data.map
function (check Array.prototype.map specification) converts one array (data
in your case) to a new array. The conversion (mapping) is defined by the argument of data.map
, also called the callback function. In your case, the callback function is the arrow function users => {console.log(users);}
. The callback function of data.map
must return a value. By returning a value for each item of the array is how data.map
defines the mapping.
But in your case the callback function does not return anything. Your intention is not to do any kind of mapping, but just to console.log
. So in your case you can use data.forEach
(Array.prototype.forEach) as you don't use data.map
functionality.
NOTE: Also you should have singular (rather than plural) name for the parameter of the callback function: data.map(user => {console.log(user);});
as this parameter is set to the individual element from the old array.
Solution 3
If you don't need to mutate the array and just do the console.log() you can do data.forEach() instead. It shouldn't give you the warning. Map expects you to return a value after you've transformed the array.
fetch('/users')
.then(res => res.json())
.then(data => {
data.forEach(users => {
console.log(users);
});
});
Solution 4
From MDN:
The map() method creates a new array with the results of calling a provided function on every element in the calling array.
That means the map method has to be returned. So,you should change your code like this:
fetch('/users')
.then(res => res.json())
.then(data => {
data.map(users => {
return console.log(users);
});
});
or use forEach() instead of map()
Solution 5
Should be a implicit return use () in place for {}.
try this
fetch('/users')
.then(res => res.json())
.then(data => {
data.map(users => (
console.log(users);
));
});
Comments
-
Chef1075 over 2 years
I'm having some issues understanding why I'm getting a compile warning on this piece of my react code
fetch('/users') .then(res => res.json()) .then(data => { data.map(users => { console.log(users); }); });
The warning I'm getting is
Expected to return a value in arrow function array-callback-return
However I'm still get the json object values from my
/users
, and they are printed to the console individually. The object is:{ id: 1, username: "Foo" }, { id: 2, username: "Bar" }
Am I missing a return statement, or am I missing something with how
map
returns values after a.then()
? I'm unclear on why the compile warning would appear at all. -
trixn over 6 yearsReturning the console log will fix the error but as
console.log()
does returnundefined
you would get an array of undefined values which will be quiet useless.forEach()
is the best choice in this case. -
trixn over 6 yearsIt expects you to return a value for an element of the array and that will be called for every element. So maybe "after you transformed the element" would make sense. Also
map()
does not mutate the array. It creates a new one. -
user_che_ban over 3 years
{} - Creates a code block that expects an explicit return statement.
that hint solved my issue. i addedreturn
to the final value -
Ondiek Elijah about 3 yearsWorks, changing the curly braces to brackets did it!
-
olisteadman almost 3 yearsWorked for me thx
-
malibil over 2 yearsyes, ı use react and i resolved my problem with this way.
-
revengeance over 2 yearsWhile this link may answer the question, it is better to include the essential parts of the answer here and provide the link for reference. Link-only answers can become invalid if the linked page changes. - From Review