Extracting only date from datetime field (mysql) and assigning it to php variable

Question

I am unable to assign only date to a php variable from datetime field of a MySQL table. I am using PHP 4, I know how to do it in PHP 5.

Can someone help as to what is missing from the below php code.

$dc = mysql_query("SELECT * FROM INVHDR WHERE Invdate BETWEEN '2011-04-01' AND '2012-03-31'");
while ($dc2 = mysql_fetch_assoc($dc)) {
    $invno      = $dc2['Invno']; // Here Invno is a datetime field type
    $invdat3    = $dc2['Invdate'];
    $date_array = explode("-", $invdat3);
    $invdat     = sprintf('%02d/%02d/%4d', $date_array[2], $date_array[1], $date_array[0]);
}

Solution 1

If you just want to display the date portion, you could use the DateTime class:

echo DateTime::createFromFormat("Y-m-d H:i:s", "2012-12-24 12:13:14")->format("d/m/Y");
// 24/12/2012

//Edited for double echo typo.

Solution 2

There is a link I find extremely useful when it comes to date manipulations: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

one can easily find the solution there:

SELECT *, DATE(Invdate) as Inv_date ...

Solution 3

Do it directly in MySQL:

select DATE_FORMAT('2012-12-24 12:13:14', '%Y/%m/%d')

So your query will look like this:

SELECT DATE_FORMAT(Invdate, '%Y/%m/%d') FROM INVHDR WHERE Invdate BETWEEN '$startdat' AND '$enddat'

Comments

[maček]

This works, but this isn't the answer. He should just be using the DATE() function in the SELECT portion of his query.

[Salman A]

I have reasons why he should be displaying/formatting dates in PHP.