Fast way to check if a number is evenly divisible by another?

Question

I was wondering what the fastest way is to check for divisibility in VB.NET.

I tried the following two functions, but I feel as if there are more efficient techniques.

Function isDivisible(x As Integer, d As Integer) As Boolean
     Return Math.floor(x / d) = x / d
End Function

Another one I came up with:

Function isDivisible(x As Integer, d As Integer) As Boolean
     Dim v = x / d
     Dim w As Integer = v
     Return v = w
End Function

Is this a more practical way?

Solution 1

Use Mod:

Function isDivisible(x As Integer, d As Integer) As Boolean
    Return (x Mod d) = 0
End Function

Solution 2

Use 'Mod' which returns the remainder of number1 divided by number2. So if remainder is zero then number1 is divisible by number2.

e.g.

Dim result As Integer = 10 Mod 5 ' result = 0

Solution 3

use the mod operator