Finding columns that are NOT NULL in PostgreSQL
98,666
Solution 1
No.
This query
SELECT DISTINCT column_name, table_name
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name IS NOT NULL
will return all the rows that have a value in the column "column_name".
All rows in that table will always have a value in the column "column_name".
Do you just need to know how many columns are nullable and how many are non-nullable?
SELECT is_nullable, COUNT(*)
FROM INFORMATION_SCHEMA.COLUMNS
GROUP BY is_nullable;
Count by table name? I think you can use this.
SELECT table_name, is_nullable, count(*)
FROM INFORMATION_SCHEMA.COLUMNS
GROUP BY table_name, is_nullable
ORDER BY table_name, is_nullable;
Solution 2
To get a count of all NOT NULL columns:
SELECT count(*)
FROM information_schema.columns
WHERE table_name = 'table_name'
AND is_nullable = 'NO';
Solution 3
To get a count of all NOT NULL columns in any table, use:
SELECT count(*)
FROM information_schema.columns
WHERE table_schema = 'table_schema_here'
AND table_name = 'table_name_here'
AND is_nullable = 'YES';
I hope this will help someone.
Author by
Admin
Updated on July 16, 2022Comments
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Admin almost 2 years
I had an assignment for each table to count nullable columns. Easy:
SELECT table_name, count(*) FROM INFORMATION_SCHEMA.COLUMNS WHERE is_nullable='NO' GROUP BY table_name;
Now I have to modify this to count "columns that have property "NOT NULL"". Will the following code do this or will it just check weather column name is not null?CREATE TEMP TABLE A AS SELECT DISTINCT column_name, table_name AS name FROM INFORMATION_SCHEMA.COLUMNS WHERE column_name IS NOT NULL GROUP BY table_name, column_name; SELECT name, count(*) FROM A GROUP BY name;
If no... Any advices?
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Daniel Waltrip almost 6 yearsFor those googlers who were looking to list all columns with a
NOT NULL
constraint:SELECT table_name, column_name FROM information_schema.columns WHERE table_schema = 'public' AND is_nullable = 'NO';
. Changetable_schema = 'public'
as needed. -
denis over 3 yearsplease add a bit of comments to your answer