Finding out if a list of Objects contains something with a specified field value?
Solution 1
I propose to create simple static method like you wrote, without any additional interfaces:
public static boolean containsId(List<DTO> list, long id) {
for (DTO object : list) {
if (object.getId() == id) {
return true;
}
}
return false;
}
Solution 2
I suggest you just override the equals
in your SearchableDto
it would be something like:
public boolean equals(Object o){
if (o instanceof SearchableDto){
SearchableDto temp = (SearchableDto)o;
if (this.id.equals(temp.getId()))
return true;
}
return false;
}
In this case contains
should work probably if it has the same id
;
Solution 3
Well, i think your approach is a bit overcomplicating the problem. You said:
I have a list of DTO received from a DB, and they have an ID.
Then probably you should use a DTO class to hold those items. If so put id getter and setter inside that class:
public class DTO implements HasId{
void setId(Long id);
Long getId();
}
That's enough for iterate through and ArrayList and search for the desired id. Extending ArrayList class only for adding the "compare-id" feautre seems overcomplicated o me. @Nikita Beloglazov make a good example. You can generalize it even more:
public boolean containsId(List<HasId> list, long id) {
for (HasId object : list) {
if (object.getId() == id) {
return true;
}
}
return false;
}
Solution 4
This is what I used in my DFS GetUnvisitedNeighbour function.
public static int GetUnvisitedNeighbour(int v)
{
Vertex vertex = VertexList.stream().filter(c -> c.Data == v).findFirst().get();
int position = VertexList.indexOf(vertex);
...
}
I used to work in C#. Lambda expressions in C# are much easier to work with than they are in Java.
You can use filter
function to add condition for property of element.
Then use findFirst().get()
or findAny.get()
according to your logic.
Sergey
Updated on July 04, 2021Comments
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Sergey almost 3 years
I have a list of DTO received from a DB, and they have an ID. I want to ensure that my list contains an object with a specified ID. Apparently creating an object with expected fields in this case won't help because contains() calls for Object.equals(), and they won't be equal.
I came up to a solution like so: created an interface
HasId
, implemented it in all my DTOs, and inherited ArrayList with a new class that hascontains(Long id)
method.public interface HasId { void setId(Long id); Long getId(); } public class SearchableList<T extends HasId> extends ArrayList<T> { public boolean contains(Long id) { for (T o : this) { if (o.getId() == id) return true; } return false; } }
But in this case I can't typecast List and ArrayList to SearchableList... I'd live with that, but wanted to make sure that I'm not inventing the wheel.
EDIT (Oct '16):
Of course, with the introduction of lambdas in Java 8 the way to do this is straightforward:
list.stream().anyMatch(dto -> dto.getId() == id);
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Sergey over 12 yearsIt was a test statement, I wanted to make sure that my Hibernate code did its mapping correctly and extracted right values from the database.
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Adriaan Koster over 12 yearsWell if this is a specific test case then why not just loop over the retrieved objects and fail the test if the desired ID is not found? Why would you have all your DTO's implement the HasId interface just for this?
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wzieba over 7 yearsFor better code readability I would remove brackets from for and if. It's good practice in my opinion. Anyway thanks for this method!
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Choletski over 7 yearshmm, not the best option in terms of performance, I think @medopal's solution is better
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Mikita Belahlazau over 7 years@Choletski what's wrong with performance here? You cannot do better than O(N) assuming that we don't use parallel computation.
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jarvo69 almost 7 yearsbetter to break the
for each
loop once flag value is true instead of looping till end