Flipping an angle using radians

11,594

Solution 1

Add/subtract pi instead.

Solution 2

You need to add Pi and then use the remainder after division by 2 Pi (to make it restricted within [0; 2 Pi] range).

JavaScript:

function invertAngle(angle) {
  return (angle + Math.PI) % (2 * Math.PI);
}
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Scott
Author by

Scott

Updated on June 04, 2022

Comments

  • Scott
    Scott about 2 years

    Hello all you math whizzes out there!

    I am struggling with a math problem I am hoping you can help me with. I have calculated an angle of direction using radians. Within OpenGL ES I move my guy by changing my point value as such:

    
    
    spriteLocation.x -= playerSpeed * cosf(playerRadAngle);
    spriteLocation.y -= playerSpeed * sinf(playerRadAngle);
    
    // playerRadAgnle is my angle of direction using radians
    
    

    This works very well to move my sprite in the correct direction. However, I have decided to keep my sprite "locked" in the middle of the screen and move the background instead. This requires me to Reverse my calculated angle. If my sprite's direction in radians is equivalent to 90 degrees, I want to convert it to 270 degrees. Again, keeping everything in radians.

    I will admit that my knowledge of Trig is poor at best. Is there a way to figure out the opposite angle using radians? I know I could convert my radians into degrees, then add/subtract 180 degrees, then convert back to radians, but I'm looking for something more efficient.

    Thanks in advance....

    -Scott

  • Scott
    Scott over 14 years
    Subtracting playerRadAngle from 2*PI works for the Y axis, but has no effect on the X axis. Since I am doing cosf() on the X and sinf() on the Y, what calculation can I make to playerRadAngle to get this done? Again, my Trig skills suck! Thanks for the quick reply!
  • Ramashalanka
    Ramashalanka over 14 years
    He didn't say subtract from 2*pi, he said add (or subtract) 1*pi. Did you try that?
  • Scott
    Scott over 14 years
    Ahhhh, he changed his post after I read it. Yes, this worked perfectly!!! Thank you both for the quick posts!