Get a PHP object property that is a number

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JSON encode, and then decode your object passing true as the second param in the decode function. This will return an associative array.

$array = json_decode(json_encode($object), true);

Now you can use your new array

echo $array['content']['5'];

Using $object->content->{'5'} will not work if the object was created by casting an array to an object.

A more detailed description can be found here: https://stackoverflow.com/a/10333200/58795

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B. Notess
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B. Notess

Updated on June 11, 2022

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  • B. Notess
    B. Notess almost 2 years

    I'm trying to get a property from JSON data decoded into a PHP object. It's just a YouTube data API request that returns a video object that has a content object liks so;

    [content] => stdClass Object
                    (
                        [5] => https://www.youtube.com/v/r4ihwfQipfo?version=3&f=videos&app=youtube_gdata
                        [1] => rtsp://v4.cache7.c.youtube.com/CiILENy73wIaGQn6pSL0waGIrxMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp
                        [6] => rtsp://v6.cache3.c.youtube.com/CiILENy73wIaGQn6pSL0waGIrxMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp
                    )
    

    Doing

    $object->content->5
    

    Throws "unexpected T_DNUMBER" - which makes perfect sense. But how do I get the value of a property that is a number?

    I'm sure I should know this. Thanks in advance.