Geting HTTP Status 400 - Required MultipartFile parameter 'file' is not present in spring

19,612

Solution 1

Spring needs the

<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />

bean to handle file-uploads.

You should register this bean in your application context file.

The Content-Type should also be valid. In your case enctype="multipart/form-data"

EDIT1:

You can give the upload and memory size to the bean properties:

  <bean id="multipartResolver"
        class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
        <!-- max upload size in bytes -->
        <property name="maxUploadSize" value="20971520" /> <!-- 20MB -->

        <!-- max size of file in memory (in bytes) -->
        <property name="maxInMemorySize" value="1048576" /> <!-- 1MB -->

    </bean>

Solution 2

when you select the file in advance rest client, on the right side there is a input box, write in that input box name of the parameter, in your case name of parameter is file

Parameter name defined here in controller @RequestParam("file")

enter image description here

Share:
19,612
Labeo
Author by

Labeo

Updated on June 16, 2022

Comments

  • Labeo
    Labeo almost 2 years

    I am trying to upload a file using spring. Below is my code how I am working on it but if I try to use it I am getting this response:

    HTTP Status 400 - Required MultipartFile parameter 'file' is not present

    I dont get what the error is.

    I am using advanced rest client for testing and I am uploading file as an attachment.

    My Javacode:

    @RequestMapping(value = "/upload",headers = "Content-Type=multipart/form-data", method = RequestMethod.POST)
        @ResponseBody
        public String upload(@RequestParam("file") MultipartFile file)
        {
            String name= "test.xlsx";
            if (!file.isEmpty()) {
                try {
                    byte[] bytes = file.getBytes();
                    BufferedOutputStream stream =
                            new BufferedOutputStream(new FileOutputStream(new File(name)));
                    stream.write(bytes);
                    stream.close();
                    return "You successfully uploaded " + name + "!";
                } catch (Exception e) {
                    return "You failed to upload " + name + " => " + e.getMessage();
                }
            } else {
                return "You failed to upload " + name + " because the file was empty.";
            }
        }