Getting 404 requested resource not available in spring restful web services

14,902

Solution 1

If you want return body then use special annotation @ResponseBody. By default controller methods annotated with @RequestMapping must return view name.

        @RequestMapping(method = RequestMethod.GET)
        @ResponseBody
        public String getHello() {
            return "hello world";
        }

EDIT:

Add <mvc:annotation-driven /> to your sample-servlet.xml.

Replace root context configuration file:

<context-param>
    <param-name>contextConfiguration</param-name>
    <param-value>/WEB-INF/sample-servlet.xml</param-value>
</context-param>

to

<context-param>
    <param-name>contextConfiguration</param-name>
    <param-value>/WEB-INF/context.xml</param-value>
</context-param>

Move all spring configuration to root context /WEB-INF/context.xml and leave /WEB-INF/sample-servlet.xml empty:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="
       http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       ">
</beans>

Solution 2

I guess you are missing the context path of your project. If you are using eclipse you can find the context path in the project properties --> Web Project settings.

Also, make sure there no errors on your console.

Solution 3

I beleive you need to put the RequestMapping for your method with a /. Something like this:

@RequestMapping(value = "/", method = RequestMethod.GET)
public String getHello() {
    return "hello world";
}
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14,902
coder
Author by

coder

Updated on June 04, 2022

Comments

  • coder
    coder about 2 years

    I'm using spring 3.2.3.RELEASE version and tomcat 7. I wanted to build a sample REST API using spring framework. My web.xml looks something like this:

    <?xml version="1.0" encoding="UTF-8"?>
    <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <context-param>
        <param-name>contextConfiguration</param-name>
        <param-value>/WEB-INF/sample-servlet.xml</param-value>
    </context-param>
    
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>sample-servlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    
    <servlet-mapping>
        <servlet-name>sample</servlet-name>
        <url-pattern>/myProjects</url-pattern>
    </servlet-mapping>
    

    My sample-servlet.xml looks something like this:

    <beans>
        <context:component-scan base-package="com.myprojects.sampleproject" />
    </beans>
    

    Basically I do not want any JSP files since I just want to return string(JSON string) from controller. My controller looks something like this:

    package com.myprojects.sampleproject;
    import org.springframework.stereotype.Controller;
    import org.springframework.web.bind.annotation.RequestMapping;
    import org.springframework.web.bind.annotation.RequestMethod;
    
    /**
     *
     * @author author
     */
    @Controller
    @RequestMapping("/user")
    public class sampleprojectController {
    
        @RequestMapping(method = RequestMethod.GET)
        public String getHello() {
            return "hello world";
        }
    }
    

    I was able to successfully create a war file and deploy it on tomcat. But when I hit localhost:8080/myProjects/user, I get 404. I'm using maven to build and deploy the package.

    I've worked on JAX-RS before where in we could configure in netbeans to create a project to write web services and everything came in handy that time. But here I'm actually trying to convert a maven based project to a web application running on tomcat. To do that, I tried this sample and I'm unable to get that up and running. Am I missing something?

  • coder
    coder almost 11 years
    I use netbeans and in project properties I dont see web project settings. Actually I had written a stand alone maven based application initially. Now I'm trying to add a wrapper to this to create REST web services. I'm not sure what I'm missing here.
  • coder
    coder almost 11 years
    logs will be available on TOMCAT_HOME/logs right? I dont see any logging happening when I hit the page. Is there any other location where I can check the logs?
  • coder
    coder almost 11 years
    I got the issue now. When I was deploying the war file to tomcat7, I'm getting this error: IOException parsing XML document from ServletContext resource [/WEB-INF/applicationContext.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/applicationContext.xml]. What exactly should be there in applicationContext.xml. I was assuming the sample-servlet.xml and web xml will suffice. Could you please explain what needs to be added in this xml?
  • coder
    coder almost 11 years
    I fixed this issue by adding applicationContext.xml. When deploying to tomcat I even got: Mapped "{[/user],methods=[GET],params=[],headers=[],consumes=[],pro‌​duces=[],custom=[]}" onto public java.lang.String com.myprojects.sampleproject.sampleprojectController.getHell‌​o(). But when I hit localhost:8080/myProjects/user, I get resource not available. In web.xml, url-pattern is /myProjects and in controller, the RequestMapping is /user. Hence Im assuming /myProjects/user is the url. Please correct me if I'm wrong.
  • seralex.vi
    seralex.vi almost 11 years
    @coder: maybe replace servlet mapping /myProjects to /myProjects/*
  • coder
    coder almost 11 years
    Finally got the issue. Netbeans had set some default context path: /<myprojectname>. So my url is /<myProjectname>/myProjects/user. I guess this is set in META-INF/context.xml.