Getting a BufferedImage as a resource so it will work in JAR file
new File("images/grass.png")
looks for a directory images on the file system, in the current directory, which is the directory from which the application is started. So that's wrong.
ImageIO.read()
returns a BufferedImage, and takes a URL or an InputStream
as argument. To get an URL of InputStream
from the classpath, you use Class.getResource()
or Class.getResourceAsStream()
. And the path starts with a /, and starts at the root of the classpath.
So, the following code should work if the grass.png file is under the package images
in the classpath:
BufferedImage image = ImageIO.read(MyClass.class.getResourceAsStream("/images/grass.png"));
This will work in the IDE is the file is in the runtime classpath. And it will be if the IDE "compiles" it to its target classes directory. To do that, the file must be under a sources directory, along with your Java source files.
fvgs
Updated on June 17, 2022Comments
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fvgs almost 2 years
I'm trying to load an image into my java application as a BufferedImage, with the intent of having it work in a JAR file. I tried using
ImageIO.read(new File("images/grass.png"));
which worked in the IDE, but not in the JAR.I've also tried
(BufferedImage) new ImageIcon(getClass().getResource( "/images/grass.png")).getImage();
which won't even work in the IDE because of a NullPointerException. I tried doing it with ../images, /images, and images in the path. None of those work.
Am I missing something here?
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fvgs almost 11 yearsMy images folder (not package) is outside of the src folder, but within the project folder in Eclipse. So I need to move the images folder into src?
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JB Nizet almost 11 yearsYes. You must do that. If you don't, eclipse won't copy the images folder to the target directory, and the images thus won't be part of the runtime classpath.
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fvgs almost 11 yearsIndeed, there we go. It's working properly now. Thanks for the help.
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Jad Chahine about 8 years@JBNizet : Perfect answer.