Getting Original Path from FileStream

Question

Given a System.IO.FileStream object, how can I get the original path to the file it's providing access to?

For example, in the MyStreamHandler() function below, I want to get back the path of the file that created the FileStream:

public static void Main() 
{
    string path = @"c:\temp\MyTest.txt";
    FileStream fs = File.Create(path));

    MyStreamHandler(fs);
    MyOtherStreamHandler(fs);

    fs.Close();
    fs.Dispose();
}

private static void MyStreamHandler(FileStream fs)
{
    // Get the originating path of 'fs'
} 

private static void MyOtherStreamHandler(FileStream fs)
{
}

Solution 1

The FileStream's Name property.

See documentation in MSDN

Solution 2

You can use fs.Name to get the path.

Solution 3

Use FileInfo-Class for getting the path.

var fileStream = File.OpenRead(fileName);
var fileInfo = new FileInfo(fileName);

Settings.Default.ThePath = fileInfo.DirectoryName;
Settings.Default.Save();

Comments

[Admin]

Thanks for answering what was apparently an RTFM-type question. I did actually, but it wasn't obvious to me that Name got the path.

[Adrian Carr]

I hate to say it, but why read the manual when you have StackOverflow? It's sooo much faster to find, with examples by people that use the technology.

[Hi-Angel]

@AdrianCarr because the manual has example whilst the answer not 😛

[Andrei Orlov]

FYI: If the absolute path is not known, this property returns a string similar to "[Unknown]". It's the case when FileStream was instantiated using SafeFileHandle.