Given a list of values remove first occurrence

Question

def drop dest(routes,location):
    for i in range(len(routes)):
        if routes[i] == location:
              routes.remove(routes[i])
    return routes

I am using a function definition given a list as
routes = [(3,2),(2,4),(5,5),(2,4)], and say I just want to remove the first occurrence value of (2,4). I am a little confused in how to do this because I do remove the value but I also remove the other value given. Where I just want to remove the first given value.

Solution

It's simple, use list.remove.

>>> routes = [(3,2),(2,4),(5,5),(2,4)]
>>> routes.remove((2,4))
>>> routes
[(3, 2), (5, 5), (2, 4)]

Comments

[brian012]

I understand that but using my code with the for loop, because my code removes all the value that match it. How do you I fix my code to just remove the first value

[timgeb]

@brian012 because your for loop keeps going after the first removal. You could add a break to the if block.