Given an angle and length, how do I calculate the coordinates

28,207

Solution 1

// edit to add conversion
    #define radian2degree(a) (a * 57.295779513082)
    #define degree2radian(a) (a * 0.017453292519)

        x = start_x + len * cos(angle);
        y = start_y + len * sin(angle);

Solution 2

You don't say what the angle is measured relative to, or indeed what direction your axes go. These will make a difference.

You first need to convert from degrees to radians (multiply by PI and divide by 180). Then you need to take the sine and the cosine of your angle and multiply these by the length of the line. You now have two numbers for your coordinates, but it depends what directions your axes go and from where you're measuring your angles which of these values is the x coordinate and which is the y, and whether either of them needs to be negated.

Solution 3

// Here is a complete program with the solution in C and command-line parameters
// Compile with the math library: 
//    gcc -Wall -o point_on_circle -lm point_on_circle.c
//
// point_on_circle.c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

double inline degree2radian(int a) { return (a * 0.017453292519); }

void getEndPoint(double angle, int len, int start_x, 
    int start_y, int *end_x, int *end_y) {
        *end_x = start_x + len * cos(angle);
        *end_y = start_y + len * sin(angle);
} // getEndPoint

int main(int argc, char *argv[]) {
  double angle = atoi(argv[1]);
  int length   = atoi(argv[2]);
  int start_x  = atoi(argv[3]);
  int start_y  = atoi(argv[4]);
  int x, y;

  getEndPoint(degree2radian(angle), length, start_x, start_y, &x, &y);
  printf("end x=%d, end y=%d\n", x, y);

  return 0;
} // main

Solution 4

math.h has all the trigonometric functions you should need. You may need to give -lm to your linker, depending on what system you're building on (sometimes it's automatic).

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amanda
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amanda

Updated on July 09, 2022

Comments

  • amanda
    amanda almost 2 years

    Assuming the upper left corner is (0,0) and I'm given an angle of 30 degrees, a starting point of (0,300), a line length of 600, how do I calculate the ending point of the line so that the line is representative of the angle given.

    The C pseudo-code is

    main() {
      int x,y;
    
      getEndPoint(30, 600, 0, 300, &x, &y);
      printf("end x=%d, end y=%d", x, y);
    }
    
    // input angle can be from 0 - 90 degrees
    
    void getEndPoint(int angle, int len, int start_x, int start_y, int *end_x, int *end_y) 
    {
    
        calculate the endpoint here for angle and length
    
        *end_x = calculated_end_x;
        *end_y = calculated_end_y;
    }