Got "syntax error near unexpected end of file" in bash script

Question

I'm making an script that gives me a day like this jjj/yyyy when I give it a day like this dd/mm/yyyy and I need it to have an error when you don't write correctly but I'm starting and it's not working :(

#! /bin/bash

#Primero debes ingresar el mes
echo "Ingresa el número de un mes del año"
read mes

#Condicional 
#Dependiendo si coloca bien $mes
if [ "$mes" -lt 12 -a "$mes" -gt 0 ]; then
echo "muy bien, sigamos."
    else
    if [ "$mes" -gt 12 -a "$mes" -lt 0 ]; then
    echo "Creo que eso ya no es un mes!";
exit
fi

When I run it it says "syntax error near unexpected end of file"

Solution

You missed a fi for inner if:

if [ "$mes" -lt 12 -a "$mes" -gt 0 ]; then
  echo "muy bien, sigamos."
else
  if [ "$mes" -gt 12 -a "$mes" -lt 0 ]; then
    echo "Creo que eso ya no es un mes!"
    # Missed fi here
  fi
  exit
fi

Comments

[Anthon]

Yes, someone can help you.

[Stéphane Chazelas]

Your code doesn't make sense. A number cannot be at the same time less than 0 and greater than 12, so your second condition can never be true. Also note that -lt and -gt are for strictly greater. -lt 12 and -gt 0 means from 1 to 11. Use -le for less than or equal.

[Divshah]

Now I have another issue, it doesn't display the second if part... I mean, If I put the number 13 it just ends, it doesn't say "Creo que esto ya no es un mes!"

[cuonglm]

@Divshah: 13 is not greater than 12 and less than 1

[Ramesh]

@Divshah, change your -a flag in the second if loop to -o.

[Divshah]

Finally I wrote this: