grep and awk parse line

Question

I have e a line that looks like:

Feb 21 1:05:14 host kernel: [112.33000] SRC=192.168.0.1 DST=90.90.90.90 PREC=0x40 TTL=51 ....

I would like to the a list of uniq IPs from SRC=

How can I do this? Thanks

Solution 1

This will work, although you could probably simplify it further in a single awk script if you wanted:

awk  '{print $7}' <your file> | awk -F= '{print $2}' | sort -u

Solution 2

grep -o 'SRC=\([^ ]\+\)' | cut -d= -f2 | sort -u

Comments

[Dr. belisarius]

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[glenn jackman]

I'd write awk '{split($7, a, /=/); print a[2]}' file | sort -u to avoid calling awk twice

[glenn jackman]

that will emit the prefix SRC= for each line

[Dr. belisarius]

@glenn I think that is OK. As the OP commented "Thanks everybody!" before I answered, so I think my answer was left unread. In any case, a substr(i,5) solves the problem, if there is one.

[kvista]

... and there you go! (I have tremendous faith in awk :-) Thanks glenn.