Groovy XmlSlurper: Find elements in XML structure

Question

Let's say there is the following XML structure:

<Data>
    <DataFieldText>
        <DataFieldName>Field #1</DataFieldName>
        <DataFieldValue>1</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #2</DataFieldName>
        <DataFieldValue>2</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #3</DataFieldName>
        <DataFieldValue>3</DataFieldValue>
    </DataFieldText>
</Data>

Using Groovy's XmlSlurper I need to do the following:

Beginning from Data find that element which contains the value Field #1in the <DataFieldName> element. If found then get the value of the corresponding <DataFieldValue> which belongs to the same level.

Solution

If DataFieldName is unique in a file:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.find {it.DataFieldName == "Field #1"}
    .DataFieldValue.text()

If it is not, and you want to get an array with all matching DataFieldValues:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.findAll {it.DataFieldName == "Field #1"}*.DataFieldValue*.text()

Comments

[Dónal]

very impressive, after reading this I feel compelled to go and refactor all my XmlSlurper code (curse you)

[tim_yates]

Isn't that a List of NodeChildren? Better might be: new XmlSlurper().parseText( xml ).DataFieldText.findAll { it.DataFieldName.text() == 'Field #1' }*.DataFieldValue*.text()

[buczek]

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