Grouping by with Where conditions in Pandas

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It seems you need query or boolean indexing first for filtering:

pauses.query("pause_end > pause_start")
       .groupby(["subscription_id"])["dif_pause"].mean().reset_index(name="avg_pause")

pauses[pauses["pause_end"] > pauses["pause_start"]]
      .groupby(["subscription_id"])["dif_pause"].mean().reset_index(name="avg_pause")
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Keithx
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Keithx

Updated on June 05, 2022

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  • Keithx
    Keithx almost 2 years

    Have a dataframe like this:enter image description here

    I created column 'dif_pause' based on subtracting 'pause_end' and 'pause_start' column values and doing the mean value aggregation using groupby () function just like this:

    pauses['dif_pause'] = pauses['pause_end'] - pauses['pause_start']
    pauses['dif_pause'].astype(dt.timedelta).map(lambda x: np.nan if pd.isnull(x) else x.days)
    
    pauses_df=pauses.groupby(["subscription_id"])["dif_pause"].mean().reset_index(name="avg_pause")
    

    I'd like to include in the groupby section the checking whether pause_end>pause_start (some equialent of WHERE clause in SQL). How can one do that?

    Thanks.