How can I force an HTML5 audio element to buffer an entire song?

16,194

Solution 1

The solution I found was this:

function load() {
    a.play();
    setTimeout("a.pause()", 10);
}

Play the file and pause it 10ms later, then the browser will buffer the entire song.

Solution 2

You can use the load() method. This basically forces preload="auto". But it probably won't buffer the whole thing.

I had the issue that audio wasn't preloaded on mobile devices (even with preload=auto), but this method worked.

http://www.whatwg.org/specs/web-apps/current-work/multipage/the-video-element.html#dfnReturnLink-2

Another option is to load the data via an XMLHttpRequest as a binary blob and set the <audio> element's src attribute to the blob URI.

(I personally don't really like the play/pause hack.)

Solution 3

You could set the preload="auto" attribute. It's not guaranteed to do anything, but it's supposed to tell the user agent to buffer as much as it wants without concern for the remote end. http://www.whatwg.org/specs/web-apps/current-work/multipage/video.html#attr-media-preload

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George
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George

Updated on June 17, 2022

Comments

  • George
    George almost 2 years

    I'm developing a local server that will stream a user's audio files so they can access them via web browsers using the HTML5 audio object. Since these files are on the user's computer, I expect the files to be buffered completely when they are loaded, but for certain large files, the songs get buffered part of the way, then stop, and resume buffering some time later.

    My question is: how can I force the audio object to buffer the entire song at once? Can I do this from javascript, do I have to set an attribute on the audio object, or is there anything else I can do?

  • Tamas Czinege
    Tamas Czinege about 12 years
    setTimeout(a.pause, 10) is better karma
  • Ahi Tuna
    Ahi Tuna about 12 years
    That works when your not passing the function any variables, sure. But why bother switching back and forth between two methods?
  • nickf
    nickf about 12 years
    @DrJokepu Actually, that wouldn't work, since you'd lose the context of the function. Better: setTimeout(a.pause.bind(a), 10)