How can I get the Unix permission mask from a file?
Solution 1
os.stat
is a wrapper around the stat(2) system call interface.
>>> import os
>>> from stat import *
>>> os.stat("test.txt") # returns 10-tupel, you really want the 0th element ...
posix.stat_result(st_mode=33188, st_ino=57197013, \
st_dev=234881026L, st_nlink=1, st_uid=501, st_gid=20, st_size=0, \
st_atime=1300354697, st_mtime=1300354697, st_ctime=1300354697)
>>> os.stat("test.txt")[ST_MODE] # this is an int, but we like octal ...
33188
>>> oct(os.stat("test.txt")[ST_MODE])
'0100644'
From here you'll recognize the typical octal permissions.
S_IRWXU 00700 mask for file owner permissions
S_IRUSR 00400 owner has read permission
S_IWUSR 00200 owner has write permission
S_IXUSR 00100 owner has execute permission
S_IRWXG 00070 mask for group permissions
S_IRGRP 00040 group has read permission
S_IWGRP 00020 group has write permission
S_IXGRP 00010 group has execute permission
S_IRWXO 00007 mask for permissions for others (not in group)
S_IROTH 00004 others have read permission
S_IWOTH 00002 others have write permission
S_IXOTH 00001 others have execute permission
You are really only interested in the lower bits, so you could chop off the rest:
>>> oct(os.stat("test.txt")[ST_MODE])[-3:]
'644'
>>> # or better
>>> oct(os.stat("test.txt").st_mode & 0o777)
Sidenote: the upper parts determine the filetype, e.g.:
S_IFMT 0170000 bitmask for the file type bitfields
S_IFSOCK 0140000 socket
S_IFLNK 0120000 symbolic link
S_IFREG 0100000 regular file
S_IFBLK 0060000 block device
S_IFDIR 0040000 directory
S_IFCHR 0020000 character device
S_IFIFO 0010000 FIFO
S_ISUID 0004000 set UID bit
S_ISGID 0002000 set-group-ID bit (see below)
S_ISVTX 0001000 sticky bit (see below)
Solution 2
I think this is the clearest way of getting a file's permission bits:
stat.S_IMODE(os.lstat("file").st_mode)
If the file is a symlink, os.lstat()
will give you the mode of the link itself, whereas os.stat()
dereferences the link. Therefore I find os.lstat()
the most generally useful.
stat.S_IMODE()
gets "the file’s permission bits, plus the sticky bit, set-group-id, and set-user-id bits".
Here's an example case, given regular file "testfile" and symlink to it, "testlink":
import stat
import os
print oct(stat.S_IMODE(os.lstat("testlink").st_mode))
print oct(stat.S_IMODE(os.stat("testlink").st_mode))
This script outputs the following for me:
0777
0666
Solution 3
Another way to do it if you don't want to work out what stat means is to use the os.access command http://docs.python.org/library/os.html#os.access BUT read the docs about possible security issues
For instance to check permissions on the file test.dat which has read/write permissions
os.access("test.dat",os.R_OK)
>>> True
#Execute permissions
os.access("test.dat",os.X_OK)
>>> False
#And Combinations thereof
os.access("test.dat",os.R_OK or os.X_OK)
>>> True
os.access("test.dat",os.R_OK and os.X_OK)
>>> False
Solution 4
oct(os.stat('file').st_mode)[4:]
Solution 5
os.access(path, mode)
method returns True
if access is allowed on path, False
if not.
available modes are :
- os.F_OK - test the existence of path.
- os.R_OK - test the readability of path.
- os.W_OK - test the writability of path.
- os.X_OK - test if path can be executed.
for example, checking file /tmp/test.sh has execute permission
ls -l /tmp/temp.sh
-rw-r--r-- 1 * * 0 Mar 2 12:05 /tmp/temp.sh
os.access('/tmp/temp.sh',os.X_OK)
False
after changing the file permission to +x
chmod +x /tmp/temp.sh
ls -l /tmp/temp.sh
-rwxr-xr-x 1 * * 0 Mar 2 12:05 /tmp/temp.sh
os.access('/tmp/temp.sh',os.X_OK)
True
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Admin
Updated on July 08, 2022Comments
-
Admin almost 2 years
How can I get a file's permission mask like 644 or 755 on *nix using python?
Is there any function or class for doing that? Thank you very much!
-
ncoghlan about 12 yearsI mostly like this answer, but bit masking seems cleaner than string slicing:
oct(os.stat("test.txt").st_mode & 0777)
-
J.J almost 9 yearsoct(os.stat("test.txt")[ST_MODE])[-3:] does not work on OSX. Instead use oct(os.stat("test.txt")[0])[-3:] or the .st_mode & 0777
-
Carson Myers almost 9 years@user3329564 it works for me -
ST_MODE
is in thestat
module, did you import it? -
patryk.beza almost 7 yearsNote that in Python 3 there is new syntax for octals, thus the output for the above example is:
0o777
and0o666
instead of0777
and0666
. -
jerblack almost 6 years
os.stat
looks like it is returning a named tuple, so you can just access its values using dotted notation.>> os.stat('.bashrc').st_mode
33188
>> os.stat('.bashrc').st_uid
1000
So no need toimport stat
. -
wjandrea about 2 yearsSince
stat.S_IMODE()
also includes the sticky, SGID, and SUID bits, the octal numbers might be up to 4 digits, so for display, it'd be better to 0-pad them to 4 digits:format(stat.S_IMODE(...), '#06o')
(using 6 instead of 4 since the prefix0o
counts), which results in0o0777
and0o0666
.