How do I clone a range of array elements to a new array?

461,677

Solution 1

You could add it as an extension method:

public static T[] SubArray<T>(this T[] data, int index, int length)
{
    T[] result = new T[length];
    Array.Copy(data, index, result, 0, length);
    return result;
}
static void Main()
{
    int[] data = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
    int[] sub = data.SubArray(3, 4); // contains {3,4,5,6}
}

Update re cloning (which wasn't obvious in the original question). If you really want a deep clone; something like:

public static T[] SubArrayDeepClone<T>(this T[] data, int index, int length)
{
    T[] arrCopy = new T[length];
    Array.Copy(data, index, arrCopy, 0, length);
    using (MemoryStream ms = new MemoryStream())
    {
        var bf = new BinaryFormatter();
        bf.Serialize(ms, arrCopy);
        ms.Position = 0;
        return (T[])bf.Deserialize(ms);
    }
}

This does require the objects to be serializable ([Serializable] or ISerializable), though. You could easily substitute for any other serializer as appropriate - XmlSerializer, DataContractSerializer, protobuf-net, etc.

Note that deep clone is tricky without serialization; in particular, ICloneable is hard to trust in most cases.

Solution 2

You can use Array.Copy(...) to copy into the new array after you've created it, but I don't think there's a method which creates the new array and copies a range of elements.

If you're using .NET 3.5 you could use LINQ:

var newArray = array.Skip(3).Take(5).ToArray();

but that will be somewhat less efficient.

See this answer to a similar question for options for more specific situations.

Solution 3

Have you considered using ArraySegment?

http://msdn.microsoft.com/en-us/library/1hsbd92d.aspx

Solution 4

I see you want to do Cloning, not just copying references. In this case you can use .Select to project array members to their clones. For example, if your elements implemented IClonable you could do something like this:

var newArray = array.Skip(3).Take(5).Select(eachElement => eachElement.Clone()).ToArray();

Note: This solution requires .NET Framework 3.5.

Solution 5

The following code does it in one line:

// Source array
string[] Source = new string[] { "A", "B", "C", "D" };
// Extracting a slice into another array
string[] Slice = new List<string>(Source).GetRange(2, 2).ToArray();
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user88637
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user88637

Updated on July 08, 2022

Comments

  • user88637
    user88637 almost 2 years

    I have an array X of 10 elements. I would like to create a new array containing all the elements from X that begin at index 3 and ends in index 7. Sure I can easily write a loop that will do it for me but I would like to keep my code as clean as possible. Is there a method in C# that can do it for me?

    Something like (pseudo code):

    Array NewArray = oldArray.createNewArrayFromRange(int BeginIndex , int EndIndex)
    

    Array.Copy doesn't fit my needs. I need the items in the new array to be clones. Array.copy is just a C-Style memcpy equivalent, it's not what I'm looking for.

  • Marc Gravell
    Marc Gravell almost 15 years
    That just copies the data; it won't create the new array etc; and if the array is new, we could use Array.Copy which is more efficient (no need for the additional checks/rollbacks).
  • crauscher
    crauscher almost 15 years
    Thats right, but creating a new Array is only one line of code and no new method is required. I agree that Array.Copy will work as well.
  • Ian Roke
    Ian Roke almost 15 years
    +1 I like this variation too. Jon, can you expand on why this is deemed less efficient?
  • Marc Gravell
    Marc Gravell almost 15 years
    @Jon: To match the question, wouldn't that be "Take(5)"? @Ian: the Array.Copy approach doesn't involve an enumerator, and will most-likely be a straight memcopy...
  • Jon Skeet
    Jon Skeet almost 15 years
    @Ian: The LINQ approach introduces two levels of indirection (the iterators), has to explicitly skip over items, and doesn't know how big the final array is going to be beforehand. Consider taking the second half of a two-million-element array: a simple "create target array, copy" approach will just copy the required block without touching the other elements, and in one go. The LINQ approach will walk through the array until it reaches the start point, then start taking values, building up a buffer (increasing the buffer size and copying periodically). Much less efficient.
  • user88637
    user88637 almost 15 years
    what does Array.Copy does internally . is it shallow copy ? C-Style memcopy?
  • Lasse V. Karlsen
    Lasse V. Karlsen almost 15 years
    Yes, it is a memcopy-type copy.
  • user88637
    user88637 almost 15 years
    So what you are actually telling me is that Array.Copy is good only for primitives.
  • Marc Gravell
    Marc Gravell almost 15 years
    No... just that with classes it'll copy the reference - it won't create a new instance.
  • user88637
    user88637 almost 15 years
    but what if I want my references to be cloned?
  • Marc Gravell
    Marc Gravell almost 15 years
    Then... tough; it doesn't do that.... you'd probably need to use serialization to achieve something similar
  • Zr40
    Zr40 almost 15 years
    No, bar will still be null. Array.Copy doesn't magically create a new array, especially since bar isn't passed with ref or out.
  • ShuggyCoUk
    ShuggyCoUk almost 15 years
    see my answer for some alternates and a link to several implementations. the part about doing it to a sub array is really rather trivial, what you really want is the cloning bit and that's a complex and somewhat open question which depends entirely on your expectations of what 'correct' behaviour should be.
  • ShuggyCoUk
    ShuggyCoUk almost 15 years
    Yes I noted the null check but didn't want to confuse the OP in case he didn't read the source.
  • Donald Byrd
    Donald Byrd almost 15 years
    Shoudn't that be something like result[i-index] = (T)... ?
  • Stan R.
    Stan R. almost 15 years
    this is a pretty creative way of doing a deep copy, very nice
  • Philippe Leybaert
    Philippe Leybaert almost 15 years
    yes :) And not only that. The loop boundary is wrong. I'll fix it. Thanks!
  • Marcus Griep
    Marcus Griep almost 15 years
    This is nice. And it especially good to point out that ICloneable is unreliable, because oh, is it ever.
  • RandomNickName42
    RandomNickName42 almost 15 years
    I think I've been making some good friend's here.... same answer as you ;) and I got voted down plenty!! hah!! Anyhow, good times good times.
  • Marc Gravell
    Marc Gravell almost 15 years
    Whether serialization calls your constructors is up to the specific serializer. Some do, some don't. But those that don't typically offer callback support to allow you to do any fixups required.
  • Hans Malherbe
    Hans Malherbe almost 15 years
    This highlights another friction point of serialization: You have to provide default constructors.
  • Robert P
    Robert P over 14 years
    Fantastic! If this does what I think it does, this solves my problem exactly.
  • Guffa
    Guffa over 14 years
    @Robert: No, it's not. Try to use an ArraySegment instead, and you see than you can neither access the items by index, not iterate throught the items.
  • Alex Black
    Alex Black over 14 years
    It probably does what you want, but it doesn't support the default array syntax, nor does it support IEnumerable, so its not especially clean.
  • Håvard S
    Håvard S over 14 years
    Just a sidenote: The latest version of Copyable on GitHub does not require objects to have a parameterless constructor. :) See github.com/havard/copyable
  • Popplars
    Popplars about 13 years
    Thanks for underlining the problems with deep cloning in C#. It's a shame really, as deep copying is a fundamental operation.
  • nawfal
    nawfal over 11 years
    This needs more upvote. In my own exp, ArraySegment copying is slightly faster too (after all I use arrays for speed critical stuffs)..
  • Ales Potocnik Hahonina
    Ales Potocnik Hahonina over 10 years
    Thanks! Works like a charm for most common needs.
  • p.s.w.g
    p.s.w.g over 10 years
    @AlexBlack It looks like as of .NET 4.5, it implements IEnumerable<T> and a variety of other useful interfaces.
  • smwikipedia
    smwikipedia about 10 years
    This is more elegant.
  • Klaus78
    Klaus78 over 9 years
    if 5 is the EndIndexm, then the correct question is array.Skip(3).Take(5-3+1).ToArray(); ie. array.Skip(StartIndex).Take(EndIndex-StartIndex+1).ToArray()‌​;
  • dragonfly02
    dragonfly02 over 9 years
    I totally agree with @nawfal, this does need more up voting and it seems that the language designers realized this is a common task now. It works just expected!
  • Exectron
    Exectron about 9 years
    How would you use ArraySegment to answer the original question?
  • Dimitris
    Dimitris almost 9 years
    Singe line and no need to add Linq. It's my preferred way.
  • nikodaemus
    nikodaemus almost 9 years
    @CraigMcQueen - Try the following single-line approach: IList<T> newArray = (IList<T>)new ArraySegment<T>(oldArray, beginIndex, endIndex);
  • I.G. Pascual
    I.G. Pascual about 8 years
    Still it doesn't clone the source... but it's a good approach anyway
  • Massimo
    Massimo over 7 years
    Does it fit .net 2 ? I got errors about missing System.Core dll.
  • Krauss
    Krauss over 7 years
    It should clone the source because ToArray: (1) creates a new array and (2) executes Array.Copy. In the end Source and Slice are two separate objects. The approach is correct, however, I prefer Array.Copy: referencesource.microsoft.com/#mscorlib/system/collections/…
  • Mike
    Mike over 6 years
    This is exactly what I was looking for. This works for any IEnumerable. I can get an IEnumerable, IList, IArray, etc... with minimal fuss, inline if I need to. If I don't need the deep copy, I just remove the Select. Dropping Skip or Take allows me to control the range. Alternatively, I can mix it up with SkipWhile and/or TakeWhile.
  • Mike
    Mike over 6 years
    @CraigMcQueen - Since the OP asked for an array, you would use var newArray = new ArraySegment(oldArray, beginIndex, endIndex - beginIndex).ToArray(). The previous comment will give you a list (i.e. not an array) that has too many elements, since it is using endIndex where a count is expected.
  • Mike
    Mike over 6 years
    This approach is only more performant if all of the following are true: you do not need a deep copy, you do not need an array and you are planning to use an enumerator to traverse the elements. Otherwise you will need multiple traversals, i.e. you are forced to do something like new ArraySegment(oldArray, offset, count).Select(e => e.Clone()).ToArray(). The approach given by @zvolkov offers a lot of flexibility, and if you can use a list instead of an array, then the approach by @eeerahul has good performance (even better if deep copy isn't required).
  • Mike
    Mike over 6 years
    EGADS! Let's start with it only works if everything being serialized is[Serializable]. If you have a very complex object, you need to ask yourself why you need the deep copy. Otherwise, consider finding a way to use struct instead of class, so Array.Copy can work. Alternatively, implement ICloneable or implement some other clone/deep copy method on the objects and only clone/copy on use.
  • Aaron Franke
    Aaron Franke over 6 years
    error: The name Array does not exist in the current context.
  • Marc Gravell
    Marc Gravell over 6 years
    @AaronFranke I don't include common using directives in most code samples. Add using System; and it should work
  • Neeraj Singh Chouhan
    Neeraj Singh Chouhan over 4 years
    ArraySegment does not support clear or remove element types methods
  • Nomnom
    Nomnom almost 3 years
    This should be the approved answer now.
  • Tinister
    Tinister almost 2 years
    .Clone() isn't necessary. The range indexer already creates a fresh array instance.