How do I copy a stack in Java?
Solution 1
Just use the clone() -method of the Stack-class (it implements Cloneable).
Here's a simple test-case with JUnit:
@Test
public void test()
{
Stack<Integer> intStack = new Stack<Integer>();
for(int i = 0; i < 100; i++)
{
intStack.push(i);
}
Stack<Integer> copiedStack = (Stack<Integer>)intStack.clone();
for(int i = 0; i < 100; i++)
{
Assert.assertEquals(intStack.pop(), copiedStack.pop());
}
}
Edit:
tmsimont: This creates a "unchecked or unsafe operations" warning for me. Any way to do this without generating this problem?
I at first responded that the warning would be unavoidable, but actually it is avoidable using <?>
(wildcard) -typing:
@Test
public void test()
{
Stack<Integer> intStack = new Stack<Integer>();
for(int i = 0; i < 100; i++)
{
intStack.push(i);
}
//No warning
Stack<?> copiedStack = (Stack<?>)intStack.clone();
for(int i = 0; i < 100; i++)
{
Integer value = (Integer)copiedStack.pop(); //Won't cause a warning, no matter to which type you cast (String, Float...), but will throw ClassCastException at runtime if the type is wrong
Assert.assertEquals(intStack.pop(), value);
}
}
Basically I'd say you're still doing an unchecked cast from ?
(unknown type) to Integer
, but there's no warning. Personally, I'd still prefer to cast directly into Stack<Integer>
and suppress the warning with @SuppressWarnings("unchecked")
.
Solution 2
Stack
extends Vector
, so you can just new up a new Stack
and use .addAll(...)
to copy the items:
Stack<Type> newStack = new Stack<Type>();
newStack.addAll(oldStack);
Solution 3
The Stack class is a sub-class of AbstractList.
Simply treat it like an AbstractList, iterate through the elements in the stack using the get(int index)
method, from 0 to the length of your list/stack, and add the elements to the new stack.
This won't copy the elements - it will add the elements to the new stack. If you need to copy the elements as well, you'll need to go another level deep and create copies of the elements, and add those to the new stack.
You can do full (or "deep") copies, by using the clone
method, but note that the object must implement the Clonable interface in order to get deep copies of objects.
Admin
Updated on January 29, 2020Comments
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Admin over 4 years
I have a stack A and I want to create a stack B that is identical to stack A. I don't want stack B to simply be a pointer to A -- I actually want to create a new stack B that contains the same elements as stack A in the same order as stack A. Stack A is a stack of strings.
Thanks!
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Steve J over 12 yearsThis won't copy the member items. Both stacks will point at the same Strings.
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clstrfsck over 12 yearsStrings are immutable, so making a copy of a string doesn't help any.
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tmsimont about 9 yearsThis creates a "unchecked or unsafe operations" warning for me. Any way to do this without generating this problem?
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esaj about 9 years@tmsimont: disregard my previous comment and see the edited answer, it is possible to prevent the warning without using
@SuppressWarnings("unchecked")
. -
Script Kitty about 6 yearsThank you. This is madness.
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Pika Supports Ukraine over 5 yearsThis is almost exactly the same as the other answer you just posted. Stack Overflow does not tolerate duplicate answers. Please delete one of the answers you posted.