How do I deserialize a complex JSON object in C# .NET?

Question

I have a JSON string and I need some help to deserialize it.

Nothing worked for me... This is the JSON:

{
    "response": [{
        "loopa": "81ED1A646S894309CA1746FD6B57E5BB46EC18D1FAff",
        "drupa": "D4492C3CCE7D6F839B2BASD2F08577F89A27B4ff",
        "images": [{
                "report": {
                    "nemo": "unknown"
                },
                "status": "rock",
                "id": "7e6ffe36e-8789e-4c235-87044-56378f08m30df",
                "market": 1
            },
            {
                "report": {
                    "nemo": "unknown"
                },
                "status": "rock",
                "id": "e50e99df3-59563-45673-afj79e-e3f47504sb55e2",
                "market": 1
            }
        ]
    }]
}

I have an example of the classes, but I don't have to use those classes. I don't mind using some other classes.

These are the classes:

public class Report
{
    public string nemo { get; set; }
}

public class Image
{
    public Report report { get; set; }
    public string status { get; set; }
    public string id { get; set; }
    public int market { get; set; }
}

public class Response
{
    public string loopa { get; set; }
    public string drupa{ get; set; }
    public Image[] images { get; set; }
}

public class RootObject
{
    public Response[] response { get; set; }
}

I want to mention that I have Newtonsoft.Json already, so I can use some functions from there.

How can I do this?

Solution 1

I am using like this in my code and it's working fine

below is a piece of code which you need to write

using System.Web.Script.Serialization;

JavaScriptSerializer oJS = new JavaScriptSerializer();
RootObject oRootObject = new RootObject();
oRootObject = oJS.Deserialize<RootObject>(Your JSon String);

Solution 2

Should just be this:

var jobject = JsonConvert.DeserializeObject<RootObject>(jsonstring);

You can paste the json string to here: http://json2csharp.com/ to check your classes are correct.

Solution 3

If you use C# 2010 or newer, you can use dynamic type:

dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);

Then you can access attributes and arrays in dynamic object using dot notation:

string nemo = json.response[0].images[0].report.nemo;

Solution 4

First install newtonsoft.json package to Visual Studio using NuGet Package Manager then add the following code:

ClassName ObjectName = JsonConvert.DeserializeObject < ClassName > (jsonObject);

Solution 5

I had a scenario, and this one helped me

JObject objParserd = JObject.Parse(jsonString);

JObject arrayObject1 = (JObject)objParserd["d"];

D myOutput= JsonConvert.DeserializeObject<D>(arrayObject1.ToString());

View more solutions

Comments

[Assaf Zigdon]

i tried this, but i am only getting "The name 'does not exist in the current context" when entering to the quick view

[stevepkr84]

Did you try classes as per the website I linked? I see they are different in that they use List<T> rather than arrays in the RootObject and Response classes. Not sure if it would make a difference.

[Assaf Zigdon]

yes, i changed it for a test, but the original was from this site

[Allen Linatoc]

Could have been a good idea, but not working for me: One or more types required to compile a dynamic expression cannot be found. Are you missing a reference

[jmbmage]

FYI: this is in System.Web.Extensions.dll

[Mich]

Where can I find the RootObject class??!

[Peter Mortensen]

But will that handle the irregular types in this particular JSON (in the question). Have you actually tried to run it?

[Peter Mortensen]

But will that handle the irregular types in this particular JSON (in the question). Have you actually tried to run it?

[davidthegrey]

It handles missing json properties quite well (it will automatically convert to nullable types when it recognises properties not repeated in the arrays of objects). Of course having a c# converter class would not make sense if the json was completely irregular/randomic. In those situations, using dynamic is the way to go. In complex situations, like the project I am working on, I had to make some minor manual adjustments, eg converting some integer types to decimal (if the sample you submit does not contain fractional figures), manually adding nullables, ...

[Ann Kilzer]

Welcome to Stack Overflow. Perhaps some clearer formatting could help improve your answer.

[AntonioR]

@Mich, RootObject class was provided as part of the model classes at the end of the code of the question.

[Spencer Sullivan]

@Javal Patel - Powerful stuff! The "auto-name" mapping saves writing a lot of mapping code. Thank you for sharing!