How do I echo the financial year?

Question

I am new to PHP and I have a question on how to echo a financial year.

For echo of calendar year, I use:

<?php echo date("y"); ?>

My financial year starts on 1 July of the previous calendar year and concludes on 30 June, and I want to echo the financial year.

I have no any idea how I can do it. I searched for answers to this problem but I cannot find an easy solution for me.

Expected output

If it is sometime in June 2015, I want to print 2015 as the year, and it would then print 2016 starting on the first day of the following month.

Solution 1

try something like:

if ( date('m') > 6 ) {
    $year = date('Y') + 1;
}
else {
    $year = date('Y');
}

Short hand notation:

$year = ( date('m') > 6) ? date('Y') + 1 : date('Y');

Solution 2

Try this:

if (date('m') <= 6) {//Upto June 2014-2015
    $financial_year = (date('Y')-1) . '-' . date('Y');
} else {//After June 2015-2016
    $financial_year = date('Y') . '-' . (date('Y') + 1);
}

Solution 3

Its too Simple

if (date('m') >= 6) {
    $year = date('Y') + 1;
} else {
    $year = date('Y');
}

try this one!

Solution 4

That should be simple enough, something like:

if (date('m') <= 6) {
    $year = date('Y');
} else {
    $year = date('Y') + 1;
}

Alternatively, you could use an single expression that maps the month to a zero/one value depending on whether it's in the first or second half of the calendar year, then adds that to your calendar year:

$year = date('Y') + (int)((date('m') - 1) / 6);

Solution 5

For India,financial year start from April of every Year.

Mostly in FY 2019-20 format

For that use following code:

//for current date month  used *** date('m')

    $date=date_create("2019-10-19");

    echo "<br> Month: ".date_format($date,"m");
    if (date_format($date,"m") >= 4) {//On or After April (FY is current year - next year)
        $financial_year = (date_format($date,"Y")) . '-' . (date_format($date,"y")+1);
    } else {//On or Before March (FY is previous year - current year)
        $financial_year = (date_format($date,"Y")-1) . '-' . date_format($date,"y");
    }

    echo "<br> FY ".$financial_year;

// O/P : FY 2019-20

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Comments

[Danny Beckett]

I don't think this is right. If my financial year starts in April (not July like the OP) then I'd swap 6 for 3. Assuming we're currently in January 2019 then $m = 1 but echo date('Y', mktime(0, 0, 0, 3+$m)); outputs 2019 when it should output 2018 until the end of March 2019. ideone.com/f010Lx