How do I only count visible rows when using the COUNTIFS function?

48,487

Solution 1

Simple way is to add another column to table - e.g. called helper with a formula like this

=SUBTOTAL(103, B2)

where column B is Result column

Now change formula to

=COUNTIFS(Table1[Result],"Fail", Table1[Comments], "",Table1[Helper],1)

the subtotal formula only returns 1 on visible rows

Without a helper column you can use this formula

=SUMPRODUCT((Table1[Result]="Fail")*(Table1[Comments]=""),SUBTOTAL(103,OFFSET(Table1[Result],ROW(Table1[Result])-MIN(ROW(Table1[Result])),0,1,1)))

Solution 2

I use this formula: =subtotal(3,B2:B100) where subtotal(3, that is CountA and B2:b100 is the range. The hidden rows in a filter are ignored and this formula only counts the visible rows. It works for me and hope it works for you

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Ajedi32
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Ajedi32

Full stack web developer/Linux admin/DevOps guy with experience in a broad range of topics including Ruby on Rails, Docker, Bash, JavaScript, PowerShell, git, etc.

Updated on August 03, 2022

Comments

  • Ajedi32
    Ajedi32 almost 2 years

    I've been using Excel's COUNTIFS function to count the number of rows in a table that meet certain criteria, E.g:

    =COUNTIFS(Table1[Result],"Fail", Table1[Comments], "")
    

    Now I want to modify this expression so that it only counts rows in Table1 that are visible. (I.E. Not filtered out.) How can I accomplish this?

  • Ajedi32
    Ajedi32 over 11 years
    That seems to work. Unfortunately, it's also triggering a weird bug in Excel that's making it very difficult to filter the table: answers.microsoft.com/en-us/office/forum/office_2007-excel/… Do you know of any other way of checking for visible rows that I might be able to use to work around this bug?
  • barry houdini
    barry houdini over 11 years
    there is a way without helper column - I'll edit my answer in 30 mins, currently on the train (!)
  • SeanC
    SeanC over 11 years
    this explains the problem and the fix - change the SUBTOTAL formula to =--SUBTOTAL(103, B2)
  • barry houdini
    barry houdini over 11 years
    +1 Sean, never seen that before. Looks like it's sorted but I posted the formula as promised - that should work without need for a helper column