How do I transpose a table in Pentaho Kettle from rows to columns without the header column

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You have to add the value name (A and B) to the row. And then first do a Row Normaliser, to make rows. Then you have to Row denormaliser, to get the two different values on the same row.

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Convert string date, to date for correct sort: Screenshot of select values

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Slaski
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Slaski

Updated on June 16, 2022

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  • Slaski
    Slaski almost 2 years

    I'm new to Pentaho and I need to transpose a table from rows to columns, but the first column doesn't contain the headers.

    It looks something like this:

    Jan/15  Feb/15  Mar/15  Apr/15
    1.1     3.4     1.7     2.0
    2.5     4.5     2.4     3.3
    

    And I need to convert to a table like the on below:

    Month   Value A  Value B
    Jan/15  1.1      2.5
    Feb/15  3.4      4.5
    Mar/15  1.7      2.4
    Apr/15  2.0      3.3
    

    Someone knows how can I achieve this? Is there some step that could help or only through scripts?