How do you make a range in Rust?

36,693

Solution 1

As of 1.0, for loops work with values of types with the Iterator trait.

The book describes this technique in chapter 3.5 and chapter 13.2.

If you are interested in how for loops operate, see the described syntactic sugar in Module std::iter.

Example:

fn main() {
    let strs = ["red", "green", "blue"];

    for sptr in strs.iter() {
        println!("{}", sptr);
    }
}

(Playground)

If you just want to iterate over a range of numbers, as in C's for loops, you can create a numeric range with the a..b syntax:

for i in 0..3 {
    println!("{}", i);
}

If you need both, the index and the element from an array, the idiomatic way to get that is with the Iterator::enumerate method:

fn main() {
    let strs = ["red", "green", "blue"];

    for (i, s) in strs.iter().enumerate() {
        println!("String #{} is {}", i, s);
    }
}

Notes:

  • The loop items are borrowed references to the iteratee elements. In this case, the elements of strs have type &'static str - they are borrowed pointers to static strings. This means sptr has type &&'static str, so we dereference it as *sptr. An alternative form which I prefer is:

      for &s in strs.iter() {
          println!("{}", s);
      }
    

Solution 2

Actually, the Loops section of the tutorial does cover for loops:

When iterating over a vector, use for instead.

for elt in ["red", "green", "blue"] {
   std::io::println(elt);
}

But if you needed indices, you could do something like the following, using the uint::range function from the core library (or int::range or u8::range or u32::range or u64::range) and Rust's syntax for blocks:

range(0u, 64u, {|i| C[i] = A[i] + B[i]});

Rust used to support this equivalent syntax but it was later removed:

range(0u, 64u) {|i|
    C[i] = A[i] + B[i];
}

Solution 3

for i in range(0, 100) is now deprecated in favour of for i in 0..100 (according to rustc 1.0.0-nightly.

Also worth noting is the compiler can't disambiguate when you use an identifier in the range (e.g., for i in 0..a), so you have to use for i in (0..a), but there's a pull request submitted to fix this.

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mcandre
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mcandre

Programmer, book reader, film scoffer.

Updated on December 28, 2021

Comments

  • mcandre
    mcandre over 2 years

    The documentation doesn't say how and the tutorial completely ignores for loops.

  • mcandre
    mcandre over 12 years
    Thanks! I'm curious why Rust has two different syntaxes for function definitions and blocks. Seems like they could save the coder trouble by reusing fn(args...) instead of |args|.
  • B. Striegel
    B. Striegel over 12 years
    @mcandre Actually, the Ruby-style block syntax {|args| body} is used to denote a closure rather than just a function. It's also really convenient for simplifying usage of anonymous functions as you might see them used in Javascript, since any function that accepts a closure as its last argument (such as a callback) can be written after the function call, as in Lindsey's third example above. Finally, even though Rust has a few different types of closures, Rust can infer the type of closure you want when using the block syntax. See also doc.rust-lang.org/doc/tutorial.html#closures
  • Warren  P
    Warren P about 11 years
    Does this still work? I can't get range(n,n) {|i| ...} to compile. I get weird errors.
  • Admin
    Admin almost 11 years
    As of rust 0.6, for int::range() |i| { C[i] = A[i] + B[i]; } should work. for is syntactic sugar which passes the closure in as an argument, iirc.
  • oli_obk
    oli_obk over 9 years
    identifier ambiguity has been fixed in github.com/rust-lang/rust/pull/21374
  • Amol
    Amol over 8 years
    if there was an int type, it has been deprecated now.
  • hellow
    hellow about 5 years
    He's right. It has been removed so this answer is obsolete.
  • Evgeni Nabokov
    Evgeni Nabokov almost 4 years
    How to make rev for 0..3?
  • Laurits L. L.
    Laurits L. L. almost 4 years
    @EvgeniNabokov Add parenthesis: for i in (0..3).rev() { // Code here... } Reference: doc.rust-lang.org/book/ch03-05-control-flow.html
  • wheeler
    wheeler over 3 years
    How do I make i a u8? I did for i: u8 in 0..26 { and it is not working.
  • zombiesauce
    zombiesauce over 2 years
    Why is this not the top answer, despite being the most voted and the accepted answer? SO works in weird ways..