How to always get a whole number if we divide two integers in c#

Question

I have three integer type variable

1. Totallistcount
2. totalpagescount
3. perpagecount

Suppose at initial level i have this

Totallistcount = 14;
perpagecount = 9;

Now I have a formula to found total number of pages possible

totalpagescount = Totallistcount / perpagecount ;

but in this situtation I got 1 in totalpagescount but I need 2 in totalpagescount , because 9 items on the first page and rest of item will be displayed on last page , How can I do this

Thanks ,

Solution 1

totalpagescount = (Totallistcount + perpagecount - 1) / perpagecount ;

Solution 2

This is how integer division should work, you need to convert it to double first to be able to get the number and then use Ceiling to "round it up":

(int)Math.Ceiling( (double)Totallistcount / perpagecount);

Solution 3

If you want to round up, you need to perform the division as a floating point number, then call Math.Ceiling to get the next-highest whole number.

double quotient = Totallistcount / (double)perpagecount;
double ceiling = Math.Ceiling(quotient);
int totalpagescount = (int)ceiling;

Solution 4

an other solution :

int pageCount = (records - 1) / recordsPerPage + 1;

int pageCount = (14 - 1) / 9 + 1; => pagecount = 2

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Comments

[Rawling]

Heh... I thought of adding the page count, realised it would break when the total count was already a multiple, and went "meh" instead of trying to figure it out properly.

[Vyktor]

+1 This is brilliant an idea, I've never though about it in this way... I'm curious though... What would be the performance difference between this solution and using Ceiling-like-solution.