How to append multiple lines to a file with bash, with "--" in front of string
Most commands that accept --foo
as an option also accept --
by itself as an "end of options, start of arguments" marker - so you could do:
printf -- "--no-color\n--format-doc\n--no-profile\n" >> ~/.rspec-test
But the more specific answer to your exact example is that the first argument to printf is a format specifier, and you're making things more difficult than necessary by not using printf for its formatting abilities. This would be a better way to do what you want:
printf "%s\n" --no-color --format-doc --no-profile >> ~/.rspec-test
That tells printf to take each argument it gets and print it, followed by a newline. Easier than repeating the \n
yourself, and it avoids the leading --
problem you were facing. And it removes the need to escape any %
signs that your strings might contain.
As for how to do multiple lines with echo
, you could use:
echo -ne "--no-color\n--format-doc\n--no-profile\n" >> ~/.rspec-test
Or, much more portably:
{ echo --no-color; echo --format-doc; echo --no-profile; } >> ~/.rspec-test
Or using cat along with a here-doc:
cat >>.rspec-test <<EOF
--no-color
--format-doc
--no-profile
EOF
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mswieboda
Updated on September 18, 2022Comments
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mswieboda over 1 year
Question very similar to How to append multiple lines to a file with bash but I want to start the file with
--
, and also append to the file, if possible.printf "--no-color\n--format-doc\n--no-profile\n" >> ~/.rspec-test
The issue is starting the file with "--" gives me a:
-bash: printf: --: invalid option printf: usage: printf [-v var] format [arguments]
Is there a way to escape the
--
? Are there any alternatives? I'm not sure how to do multiple lines usingecho
, andcat
isn't a good option, I'd like to have it in an automated script.