How to assign pointer address manually in C programming language?
Solution 1
Like this:
void * p = (void *)0x28ff44;
Or if you want it as a char *
:
char * p = (char *)0x28ff44;
...etc.
If you're pointing to something you really, really aren't meant to change, add a const
:
const void * p = (const void *)0x28ff44;
const char * p = (const char *)0x28ff44;
...since I figure this must be some kind of "well-known address" and those are typically (though by no means always) read-only.
Solution 2
Your code would be like this:
int *p = (int *)0x28ff44;
int
needs to be the type of the object that you are referencing or it can be void
.
But be careful so that you don't try to access something that doesn't belong to your program.
Solution 3
int *p=(int *)0x1234 = 10; //0x1234 is the memory address and value 10 is assigned in that address
unsigned int *ptr=(unsigned int *)0x903jf = 20;//0x903j is memory address and value 20 is assigned
Basically in Embedded platform we are using directly addresses instead of names
Irakli
I am Senior Full-Stack Software engineer with 8 years of experience. I worked with multiple successful startups remotely. I love working on products end-to-end.
Updated on December 27, 2020Comments
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Irakli over 3 years
How do you assign a pointer address manually (e.g. to memory address
0x28ff44
) in the C programming language?