How to automatically login as a user using Spring Security without knowing their password?

15,002

Solution 1

To get this to work, I had to:

Configure a reference to the UserDetailsService (jdbcUserService)

<authentication-manager>
<authentication-provider>
<jdbc-user-service id="jdbcUserService" data-source-ref="dataSource"
  users-by-username-query="select username,password, enabled from users where username=?" 
  authorities-by-username-query="select u.username, ur.authority from users u, user_roles ur where u.user_id = ur.user_id and u.username =?  " 
/>
</authentication-provider>
</authentication-manager>

Autowire my userDetailsManager in my controller:

@Autowired
@Qualifier("jdbcUserService")  // <-- this references the bean id
public UserDetailsManager userDetailsManager;

In the same controller, authenticate my user like so:

@RequestMapping("/automatic/login/test")
public @ResponseBody String automaticLoginTest(HttpServletRequest request) 
{
    String username = "[email protected]";

    Boolean result = authenticateUserAndInitializeSessionByUsername(username, userDetailsManager, request);

    return result.toString();
}

public boolean authenticateUserAndInitializeSessionByUsername(String username, UserDetailsManager userDetailsManager, HttpServletRequest request)
{
    boolean result = true;

    try
    {
        // generate session if one doesn't exist
        request.getSession();

        // Authenticate the user
        UserDetails user = userDetailsManager.loadUserByUsername(username);
        Authentication auth = new UsernamePasswordAuthenticationToken(user, null, user.getAuthorities());
        SecurityContextHolder.getContext().setAuthentication(auth);
    }
    catch (Exception e)
    {
      System.out.println(e.getMessage());

      result = false;
    }

    return result;
}

Note that a good precursor to just using spring security for your app can be found here.

Solution 2

for second problem

an admin to login as any user without knowing their password.

you should use switch user feature from spring. javadoc and article

Solution 3

This is answer to above question In Controller:

@RequestMapping(value = "/registerHere", method = RequestMethod.POST)
    public ModelAndView registerUser(@ModelAttribute("user") Users user, BindingResult result,
            HttpServletRequest request, HttpServletResponse response) {
        System.out.println("register 3");

        ModelAndView mv = new ModelAndView("/home");
        mv.addObject("homePagee", "true");

        String uname = user.getUsername();

        if (userDAO.getUserByName(uname) == null) {

            String passwordFromForm = user.getPassword();
            userDAO.saveOrUpdate(user);

            try {
                authenticateUserAndSetSession(user, passwordFromForm, request);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }


        }

        System.out.println("register 4");

        log.debug("Ending of the method registerUser");
        return mv;
    }

Further above method in controller is defined as:

`private void authenticateUserAndSetSession(Users user, String passwor`dFromForm, HttpServletRequest request){

        String username = user.getUsername();
        System.out.println("username:  " + username + " password: " + passwordFromForm);                        

        UserDetails userDetails = userDetailsService.loadUserByUsername(user.getUsername());

        UsernamePasswordAuthenticationToken usernamePasswordAuthenticationToken = new UsernamePasswordAuthenticationToken(username, passwordFromForm, userDetails.getAuthorities());
        request.getSession();

        System.out.println("Line Authentication 1");

        usernamePasswordAuthenticationToken.setDetails(new WebAuthenticationDetails(request));

        System.out.println("Line Authentication 2");

        Authentication authenticatedUser = authenticationManager.authenticate(usernamePasswordAuthenticationToken);

        System.out.println("Line Authentication 3");


        if (usernamePasswordAuthenticationToken.isAuthenticated()) {
            SecurityContextHolder.getContext().setAuthentication(authenticatedUser);
            System.out.println("Line Authentication 4");

        }

     request.getSession().setAttribute(HttpSessionSecurityContextRepository.SPRING_SECURITY_CONTEXT_KEY, SecurityContextHolder.getContext());// creates context for that session.

        System.out.println("Line Authentication 5");

        session.setAttribute("username", user.getUsername());

        System.out.println("Line Authentication 6");

        session.setAttribute("authorities", usernamePasswordAuthenticationToken.getAuthorities());

        System.out.println("username:  " + user.getUsername() + "password: " + user.getPassword()+"authorities: "+ usernamePasswordAuthenticationToken.getAuthorities());

        user = userDAO.validate(user.getUsername(), user.getPassword());
        log.debug("You are successfully register");

    }

Other answers didnt suggest to put it in try/catch so one does not realize why logic is not working as code runs...and nothing is there neither error or exception on console. So if you wont put it in try catch you wont get exception of bad credentials.

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Brad Parks
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Brad Parks

Web programmer, interested in node js, cross platform development, and automating the things!

Updated on July 06, 2022

Comments

  • Brad Parks
    Brad Parks almost 2 years

    My application uses Spring Security, and my client requires:

    • users to be able to automatically login after signup.
    • an admin to login as any user without knowing their password.

    So I need to figure out how to login as any user automatically without knowing their password.

    How can this be accomplished using Spring Security?