How to call axis apache client in java

23,802

This is due to impedence mismatch beetween the client code and the service.server is not able to decode your request, and continue processing with default values

You can try this instead

call.setOperationName(new QName("http://tempuri.org/","CelsiusToFahrenheit")); 
call.addParameter(new QName("http://tempuri.org/","Celsius"),XMLType.XSD_STRING,ParameterMode.IN);
String ret = (String) call.invoke( new Object[] {"20"} );

note the change in namespaceURI too.

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Ballon
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Ballon

Java SE, python, JMeter

Updated on June 11, 2020

Comments

  • Ballon
    Ballon almost 4 years

    I want to connect to the web service with apache axis in java and I have some wrong parameter but I don't know which:

    import org.apache.axis.client.Call;
    import org.apache.axis.client.Service;
    import javax.xml.namespace.QName;
    
     public class Test_Web_Service
     {
    
     public static void main(String [] args) throws Exception {
    
         try {
    
                String endpoint =  "http://www.w3schools.com/webservices/tempconvert.asmx";
    
                Service  service = new Service();
                Call call= (Call) service.createCall();
    
                call.setProperty( Call.SOAPACTION_USE_PROPERTY, new Boolean( true ) );
                call.setProperty( Call.SOAPACTION_URI_PROPERTY, "http://tempuri.org/CelsiusToFahrenheit");
    
                call.setTargetEndpointAddress( new java.net.URL(endpoint) );
                call.setOperationName(new QName("http://tempuri.org/CelsiusToFahrenheit","CelsiusToFahrenheit"));
    
                String ret = (String) call.invoke( new Object[] {"20"} );
                System.out.println("Sent '20', got '" + ret + "'");
    
         } catch (Exception e) {
                System.err.println(e.toString());
        }
     }
    }
    


    web service link: http://www.w3schools.com/webservices/tempconvert.asmx
    In ret variable I get message Error. Is this because I have wrong parameter in QName.