How to check if a directory is under svn version control?

Question

From a linux bash script, how can I verify if some directory is under svn version control? I am using svn version 1.7.9.

When I try the following

pushd ${WD}; svn info; popd

and check the error code I always get a zero, because popd succeeded, even if svn info returned an error. How to perform a check on a directory in the following way?

if [ ... ]; then
    echo "Directory ${WD} not under version control"
fi

Solution 1

Store the return code from the svn command in a variable and test that-:

pushd $PWD
svn info
ERR=$?
popd 
if [ $ERR -ne 0 ];then
    echo "Directory ${WD} not under version control"
fi

Solution 2

Subversion uses a hidden directory called .svn (just like .git for Git).

First, a directory not under SVN control:

riemann$ if [ ! -d ".svn" ]; then echo "Directory not under version control"; fi;
Directory not under version control
riemann$

Next, a directory which is under SVN control (Crypto++ use SVN):

riemann::cryptopp$ if [ ! -d ".svn" ]; then echo "Directory not under version control"; fi;
riemann::cryptopp$

And:

riemann::cryptopp$ ls -al .*
-rw-r--r--@ 1 jwalton  staff  6148 Jul 20 06:46 .DS_Store

.:
total 440904
drwx------  462 jwalton  staff     15708 Aug 10 16:00 .
drwx------   59 jwalton  staff      2006 Aug 10 15:50 ..
drwx------    7 jwalton  staff       238 Jul 17 07:41 .svn
...

Comments

[Alex]

I have updated the question as your suggestion does not work; I do not have a .svn directory. Maybe its depending on the version?

[Ben]

Subdirectories in SVN 1.6.x and earlier all had a .svn and could be used like a full working copy on their own. In 1.7 and higher, only the working copy root has such a directory.