How to check if input type button is pressed in PHP?

Question

The isset() function can be used to check if the input type submit is pressed, but is there a way to check if the input type button is pressed?

In my code the button does nothing but call a function on the .Onclick() event which then refreshes the page and makes a database entry inside PHP...and I want it to make the entry only after the button is pressed...and I can't use the submit type for other reasons...following is some code:

function send()
{
    var events = document.getElementById("event").value;
    location.href = "calm.php?day=" + xx + "&month=" + yy + "&year=" +
                    zz + "&events=" + events;
}

<input name="Button"
       type="button"
       id="submit"
       onclick="send(this.form)"
       value="Button" />

<?php
    session_start();
    include_once "connect_to_mysql.php";
    $day = $_GET['day'];
    $month = $_GET['month'];
    $year = $_GET['year'];
    $events = $_GET['events'];
    $userid = $_SESSION['id'];
    if (isset($_POST['button']))
    {
        $sql = mysql_query("INSERT INTO events (userid,month,day,year,events)
                            VALUES('$userid','$month','$day', '$year','$events')")
               or die (mysql_error());
    }
?>

Solution 1

isset($_POST['Button']) you just missed the capital B. You need to match it the same as the input's name attribute.

Solution 2

you need to do that using ajax. so when a user clicks this button the page won't refresh.. there should be a page behind the seen does that for the user. whenever he clicks the button it accesses that page and upload whatever data you want...

edit: or you can just add a hidden input in the form when the button is clicked the hidden input value changes to i.e. true... then from php codes you can use the isset or other functions to validate whether the user clicked the button or not...