How to check whether a string contains a substring in JavaScript?

7,162,717

Solution 1

ECMAScript 6 introduced String.prototype.includes:

const string = "foo";
const substring = "oo";

console.log(string.includes(substring)); // true

includes doesn’t have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:

var string = "foo";
var substring = "oo";

console.log(string.indexOf(substring) !== -1); // true

Solution 2

There is a String.prototype.includes in ES6:

"potato".includes("to");
> true

Note that this does not work in Internet Explorer or some other old browsers with no or incomplete ES6 support. To make it work in old browsers, you may wish to use a transpiler like Babel, a shim library like es6-shim, or this polyfill from MDN:

if (!String.prototype.includes) {
  String.prototype.includes = function(search, start) {
    'use strict';
    if (typeof start !== 'number') {
      start = 0;
    }

    if (start + search.length > this.length) {
      return false;
    } else {
      return this.indexOf(search, start) !== -1;
    }
  };
}

Solution 3

Another alternative is KMP (Knuth–Morris–Pratt).

The KMP algorithm searches for a length-m substring in a length-n string in worst-case O(n+m) time, compared to a worst-case of O(nm) for the naive algorithm, so using KMP may be reasonable if you care about worst-case time complexity.

Here's a JavaScript implementation by Project Nayuki, taken from https://www.nayuki.io/res/knuth-morris-pratt-string-matching/kmp-string-matcher.js:

// Searches for the given pattern string in the given text string using the Knuth-Morris-Pratt string matching algorithm.
// If the pattern is found, this returns the index of the start of the earliest match in 'text'. Otherwise -1 is returned.

function kmpSearch(pattern, text) {
  if (pattern.length == 0)
    return 0; // Immediate match

  // Compute longest suffix-prefix table
  var lsp = [0]; // Base case
  for (var i = 1; i < pattern.length; i++) {
    var j = lsp[i - 1]; // Start by assuming we're extending the previous LSP
    while (j > 0 && pattern[i] !== pattern[j])
      j = lsp[j - 1];
    if (pattern[i] === pattern[j])
      j++;
    lsp.push(j);
  }

  // Walk through text string
  var j = 0; // Number of chars matched in pattern
  for (var i = 0; i < text.length; i++) {
    while (j > 0 && text[i] != pattern[j])
      j = lsp[j - 1]; // Fall back in the pattern
    if (text[i]  == pattern[j]) {
      j++; // Next char matched, increment position
      if (j == pattern.length)
        return i - (j - 1);
    }
  }
  return -1; // Not found
}

console.log(kmpSearch('ays', 'haystack') != -1) // true
console.log(kmpSearch('asdf', 'haystack') != -1) // false
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gramm
Author by

gramm

Updated on March 09, 2022

Comments

  • gramm
    gramm about 2 years

    Usually I would expect a String.contains() method, but there doesn't seem to be one.

    What is a reasonable way to check for this?

  • gman
    gman over 3 years
    just curious, why do you need to check the length? Does IE fail in that case or something?
  • gman
    gman over 3 years
    Also the checking for number fails to perform like includes. Example: es6 includes returns false for "abc".includes("ab", "1") this polyfill will return true
  • Gavin
    Gavin almost 3 years
    While this is a good answer, and the OP never requested for a "case-sensitive" search, it should be noted that includes performs a case-sensitive search.
  • sphoenix
    sphoenix almost 3 years
    Not questioning anything on this approach... but why implementing KMP where there's a includes or indexOf on the table. (Although the underneath impl of those maybe using KMP... not sure)
  • wz366
    wz366 almost 3 years
    KMP provides linear O(n) performance here.
  • TheLebDev
    TheLebDev almost 3 years
    @wz366 KMP provides O(n), what about the rest? Any Idea?
  • dandavis
    dandavis over 2 years
    If this is used for speed, it would likely run faster if you replaced .charAt(i) with [i] to avoid the extra function calls.
  • Aashiq
    Aashiq over 2 years
    includes return true for empty substring .
  • Ry-
    Ry- over 2 years
    @Aashiq: Yes, an empty string is a substring of every string.
  • Davo
    Davo over 2 years
    @Gavin by default if I want to know if something is a substring, I imagine it would be case-sensitive. After all, "A" and "a" are different characters. The OP never requested a "case-insensitive" search ( which is a trivial solution, if you make everything lowercase)
  • Experimenter
    Experimenter about 2 years
    indexOf is also case case-sensitive search, so both includes and indexOf are case-sensitive .
  • KWallace
    KWallace almost 2 years
    Why is a discussion of case sensitivity even taking place here?