How to convert 'dd/mm/yyyy hh:mm:ss am/pm' to hh:mm:ss (without am or pm) in java?

Question

I want the convert the string like 1/15/2014 9:57:03 AM or 1/15/2014 5:49:39 PM to 9:57:03 and 17:49:39

Solution 1

SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a", Locale.US);
Date date = format.parse("1/15/2014 9:57:03 AM");
format = new SimpleDateFormat("HH:mm:ss");
String dateString = format.format(date);

BTW, use Google next time

Solution 2

You should see this in the doc doc SimpleDateFormat

Comments

[Vinayak Pingale]

Dont convert the string. get the time by using getTime().

[Justin]

See docs.oracle.com/javase/7/docs/api/java/lang/String.html . Take a close look at substring and indexOf

[Baby]

use SimpleDateFormat