How to create a random float in Objective-C?
Solution 1
Try this:
(float)rand() / RAND_MAX
Or to get one between 0 and 5:
float randomNum = ((float)rand() / RAND_MAX) * 5;
Several ways to do the same thing.
Solution 2
Here is a function
- (float)randomFloatBetween:(float)smallNumber and:(float)bigNumber {
float diff = bigNumber - smallNumber;
return (((float) (arc4random() % ((unsigned)RAND_MAX + 1)) / RAND_MAX) * diff) + smallNumber;
}
Solution 3
- use arc4random() or seed your random values
try
float pscale = ((float)randn) / 100.0f;
Solution 4
Your code works for me, it produces a random number between 0.15 and 0.3 (provided I seed with srandom()
). Have you called srandom()
before the first call to random()
? You will need to provide srandom()
with some entropic value (a lot of people just use srandom(time(NULL))
).
For more serious random number generation, have a look into arc4random
, which is used for cryptographic purposes. This random number function also returns an integer type, so you will still need to cast the result to a floating point type.
Solution 5
Easiest.
+ (float)randomNumberBetween:(float)min maxNumber:(float)max
{
return min + arc4random_uniform(max - min + 1);
}
Roman
Updated on November 13, 2020Comments
-
Roman over 3 years
I'm trying to create a random float between 0.15 and 0.3 in Objective-C. The following code always returns 1:
int randn = (random() % 15)+15; float pscale = (float)randn / 100;
What am I doing wrong?